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focus72050

Caculate what wednesday is it of the month

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Hi everyone,

I am looking for php code that will

return to me whether it is the first, second third or if exists fourth wednesday for the current month,  and by current month the script should decide on its own what the current month is.

Thank you in advance really appreciate it.

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[code=php:0]
$weekposA = array(1=>"first", "second", "third", "fourth");
$month = date("F"); //get the month (Januaray to December)
$day = date("j"); //get day of the week 1-31
$weekpos = ceil($day/7); //determine whether it's the 1st, 2nd, ...of the week

$theweeknum = $weekposA[$weekpos];
$todayweek = date("l");

//if($todayweek == "Wednesday")
echo "Today is the " . $theweeknum . " " . $todayweek . " of " . $month;
[/code]

To make it display on Wednesday's only, just uncomment my "if($todayweek == "Wednesday")" out.

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There are always at least four Wednesdays in a month. Sometimes there are five.

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to rework extrovertive's response slightly, all you'd have to do to find out which occurrence of the day of the week a certain date is, just run a function like this where you can pass the date to it. then, you've got a very flexible solution that you can use the results in a variety of ways:
[code]
<?php
function getWhichWeek($date = '') {
  $date = empty($date) ? date('Y-m-d') : $date; // default to today
  list($year, $month, $day) = explode('-', $date);
  $res = array(
    'day'  => date('l', strtotime($date)),
    'week' => ceil($day/7)
  );

  switch($res['week']) {
    case 1:
      $res['post'] = 'st';
      break;

    case 2:
      $res['post'] = 'nd';
      break;

    case 3:
      $res['post'] = 'rd';
      break;

    default:
      $res['post'] = 'th';
  }

  return $res;
}

$today = getWhichWeek();
echo "Today is the {$today['week']}{$today['post']} {$today['day']} of the month!";
?>
[/code]

have fun with that!

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Everyone thank you a million, I really appreciate it.  And yes you are correct there are at least 4 of each day in a month, dont know what I was thinking.

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