Extacting URL

[afrojojo]

Need some help extacting the first url from a string. Whether it would start with http or https. Thanks

 

Input

this is some text  http://yahoo.com/directory/file.php?id=1&blah=1 this is some texthttp://msn.com this is some text

this is some text https://google.com.

 

Output

http://yahoo.com/directory/file.php?id=1&blah=1

[premiso]

http://www.phpfreaks.com/forums/index.php?topic=294975.0

 

Sometimes a search of the forums works wonders. You will also find many other topics in the regex section overing this.

[afrojojo]

http://www.phpfreaks.com/forums/index.php?topic=294975.0

 

Sometimes a search of the forums works wonders. You will also find many other topics in the regex section overing this.

That's not what I asked.

[premiso]

Using that matching expression posted in the preg_replace, use it in preg_match and viola, you have the first url matched. Simple as that.

[afrojojo]

Using that matching expression posted in the preg_replace, use it in preg_match and viola, you have the first url matched. Simple as that.

Doesn't work

[cags]

With helpful information such as that, and an obvious attitude problem, I believe we will have hammered out an accurate answer for you by the 4th June 2020.

[afrojojo]

 

http://www.phpfreaks.com/forums/index.php?topic=294975.0

 

Sometimes a search of the forums works wonders. You will also find many other topics in the regex section overing this.

 

I've searched. I couldn't find anything. Thats not what my question was related to.

 

http://www.phpfreaks.com/forums/index.php?topic=294975.0

 

Sometimes a search of the forums works wonders. You will also find many other topics in the regex section overing this.

Using that matching expression posted in the preg_replace, use it in preg_match and viola, you have the first url matched. Simple as that.

I tried that. Doesn't work.

[ZachMEdwards]

<?PHP
$input = 'this is some text  http://yahoo.com/directory/file.php?id=1&blah=1  this is some texthttp://msn.com this is some texthis is some text https://google.com.';
$pattern = '/((?:https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|$!:,.;]*[A-Z0-9+&@#\/%=~_|$])/i';
if(preg_match($pattern, $input, $match)) {
	echo $match[0];
} else { 
	echo 'Not found!';
}
?>

[afrojojo]

Thanks Zach

[afrojojo]

One more question.

 

Is there a way to choose which match in the string it gets?

 

match[1] = The first url in string

match[2] = The second url in string

[salathe]

ajfrojojo, that's not how preg_match works; please read the appropriate manual page to see why. There is, however, a very similarly named function which would help lots with what you're after; I'll leave you to discover that on your own after reading the link above.

[afrojojo]

$pattern = '/((?:https?|ftp):\/\/[-A-Z0-9+&@#\/%?=~_|$!:,.;]*[A-Z0-9+&@#\/%=~_|$])/i';	
if(preg_match_all($pattern, $string, $match)) {
$string=$match[0][0];
echo $string;
}

I came up with that using preg_match_all. It's almost what I want.

 

$string = "<a href="http://google.com">Google</a> this is some text http://yahoo.com this is some texthttp://msn.com";

 

If the string was what I have above, how do I make the pattern stop at a " or '. Otherwise the first string produced would be http://google.com">Google</a>. I just want it to be http://google.com. It only stops at the first space. I would like it to stop at the first space, the first ", or the first '.

 

So I would want the output of $string=$match[0][0] to be http://google.com. The output of $string=$match[0][1] to be http://yahoo.com, and so on.

[salathe]

The pattern that you posted will stop at a quote.

[afrojojo]

I suppose I should rephrase this. I want it to stop at the first space, the SECOND quote, or the SECOND apostrophe, and begin at http:// or https://

[salathe]

Show us some sample string and code (may be the same as the previous snippet) which does not behave as you want, then be precise about how you want it to behave. Currently, the code and string in your next-to-last post work as advertised.

[afrojojo]

$pattern = '/((?:https):\/\/[-A-Z0-9+&@#\/%?=~_|$!:,.;]*[A-Z0-9+&@#\/%=~_|$])/i';

if(preg_match_all($pattern, $string, $match)) {

$string=$match[0][0];

echo $string;

}

 

Input:

http://yahoo.com this is some text

Output

http://yahoo.com

 

The above is ok

 

Input

<a  href="http://yahoo.com">Yahoo</a>

Output

http://yahoo.com"

 

I want to remove that last quote.

 

 

 

[salathe]

Neither of those inputs should output anything since the regex in your code looks for https

[afrojojo]

Oops...

 

/((?:https?):\/\/[-A-Z0-9+&@#\/%?=~_|$!:,.;]*[A-Z0-9+&@#\/%=~_|$])/i

[salathe]

The second input cannot output with a double-quote since the regex in your code cannot, ever match a double-quote.

 

Please, write show us a sample script (like what you have already, but with $string(s) being defined) that I can run, which gives you that trailing double-quote character in the match.

[afrojojo]

$string = '<a href="http://yahoo.com">Yahoo</a>';

 

$pattern = '/((?:https?):\/\/[-A-Z0-9+&@#\/%?=~_|$!:,.;]*[A-Z0-9+&@#\/%=~_|$])/i'; 

if(preg_match_all($pattern, $string, $match)) {

$string=$match[0][0];

echo $string;

}

 

Output

http://yahoo.com">Yahoo</a>

[salathe]

I cannot reproduce your output, nor can I see in your code how on earth that text can get matched.

 

See a live running example of your code (behaving properly) -- http://codepad.viper-7.com/W32a4S

 

Are you sure you're not just doing something dumb like echoing the original string rather than what was matched?

[afrojojo]

I figured out the issue. I applied htmlentities.

$string=htmlentities($string);

 

Any way around this? I don't want any other html code displayed.

[afrojojo]

I think I got it. Adding the ENT_NOQUOTES seemed to do the trick. It was encoding the quotes and messing it up.

 

$string=htmlentities($string,ENT_NOQUOTES);

 

Thanks for all your help. I appreciate it.

[salathe]

Glad you got it sorted. Next time please be sure to give accurate sample data/code, to help us to help you.