PLEASE SOMEBODY HELP ME SOLVE THESE SCENARIOS

[ciriusrob]

Can some PHP guru help me with this scenarios? I've been wondering around these for hours and can't find my way around  it. Please...

 

1.

Write a function in PHP that takes three parameters (representing day, month and year) and calculates the day/month/year of the following day (for example, if the parameter is 31/10/2010, the result should be 01/11/2010). No need to take into account leap years. You cannot use any date/time specific functions, you must do it "by hand" (no built-in functions)..

 

2.

Write a function in PHP that takes a string and counts the number of occurrences of any given letter in it (for example, given the string "HELLO" as a parameter, there are two occurrences of "L", one of "H", one of "E", one of "O" and zero of any other character).

[Pikachu2000]

Where exactly are you stuck? Post your current code.

[ciriusrob]

I screwed up in a job interview when i was presented with these scenarios. I am a newbie in programming and I couldn't even get the logic or approach around the scenario let alone coding it. Can  someone help by giving me the logic and approach in plain English so I'll try and code myself please...???

[trq]

I DON'T APPRECIATE BEING YELLED AT!!!!

 

Sounds like homework to me. We don't do homework.

[dreamwest]

I screwed up in a job interview when i was presented with these scenarios. I am a newbie in programming and I couldn't even get the logic or approach around the scenario let alone coding it. Can  someone help by giving me the logic and approach in plain English so I'll try and code myself please...???

 

Your better off developing some of your own apps first and get some exp before you even think about building apps for a company..its just easier

[ignace]

function calc_next_day($day, $month, $year) {
    // 0 = January
    $days_in_month = array(31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
    $day_count = $days_in_month[$month - 1];
    if($day + 1 > $day_count) {
        $day = 1;
        if($month + 1 > 12) {
            $month = 1;
            ++$year;
        } else {
            ++$month;
        }
    } else {
        ++$day;
    }
    return "$day/$month/$year";
}

function str_occur($string) {
    $string = preg_replace('/[^a-z]/i', '', $string);
    $string = str_split($string);
    
    return array_count_values($string);
}

 

A fun exercise You really can't do anything with it as they'll ask you questions about the code and you'll still end up screwed

[ciriusrob]

@ignace:

i don't know how to thank you. i screwed up already but i think with this i can get to practice more and understand the concept of php programming. U R MAN..

[ignace]

i don't know how to thank you

 

Add an @copyright Ignace comment line above each function