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<?php

$temp = "01";

$temp = (int)temp;

echo $temp;

?>

 

I am using above code to convert string to integer variable but i am getting incorrect output.. somehow casting chopping values in the string.  for example, above code should give me output 01 but actual output is 0.

 

any pointer? i am new to php...

 

Thanks,

Rajesh

$temp = (int)temp;

 

^^^ You don't have a defined constant named temp, so php assumed that you meant -

 

$temp = (int)'temp';

 

And, well, the (int) of the string 'temp' is zero. If you meant to use $temp, please proof read your code when it doesn't work.

first of all, i am really sorry that i did not paint clear picture of my problem.

I am getting value 01 as string after some string spilt function. Now i want to use this value as integer.

 

//function body

function converthours($temp)

{

$temp = (int)temp;

echo $temp *60;

}

 

//function call

<?php

$temp = "01";  //temp is declared as string variable with value 01. in original code, its value return by another function

converthours($temp);

?>

 

@Maq  Sorry but why 01 is not an integer?

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