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image upload problem?plz help


mattm1712

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hi i have wrote this code for uploading an image this is my main code

 

 

<?php

$lastimage2 =  mysql_query("SELECT * FROM images WHERE id=$view");

$li2 = mysql_fetch_assoc($lastimage2);

 

if ($page=="P8"&$view>0)

{

echo "<table class=roung bgcolor='#000000'><tr><TD><img src=uploaded/$li2[picname] width='760' height='540'></td></tr></table>";

include 'picclicks.php';

echo "<tr><td>Views: $clicks2 </td></tr>";

 

}

else

{

if ($_SESSION['user'])

{

If ($imagereport='1')

{

}

echo"

<table bgcolor='#000000' class=round><tr><td class=ach>

<form action='index.php?variable=".$page."&fun=upload' method='POST' enctype='multipart/form-dat'>

<input type='file' name='myfile'>

 

<input type='submit' value='Upload'>

 

</td></tr></table></form>

";

}

else

{

echo "Please Login to upload new photos!";

}

?>

 

 

then i have this for imageupload.php

 

<?php

if ($_FILES)

{

$username = $_SESSION['user'];

$date =time();

$name = $_FILES["myfile"]["name"];

$type = $_FILES["myfile"]["type"];

$size = $_FILES["myfile"]["size"];

$temp = $_FILES["myfile"]["tmp_name"];

$error = $_FILES["myfile"]["error"];

$hs=$_POST['High Score'];

$g=$_POST['Glitch'];

$f=$_POST['Funny'];

$o=$_POST['Other'];

 

$tags = new Array();

foreach($_POST['tag'] as $tag){

  if($tag){

      tags[] = $tag;

  }

}

$tag = implode(',',$tags);

 

if ($error > 0 )

die("Error uploading file! Code $error.");

else

{

if ($type =="image/jpeg")

{

include 'connect.inc';

move_uploaded_file($temp,"uploaded/".$name);

mysql_query("INSERT INTO images VALUES('','$name','','$username','$date','0','0','0','0','0','0','0','0')");

$uploadreport='1';

 

}

else

{

}

 

}

}

else

{

}

 

?>

 

my database is set right, and this is what i have in my index file

 

 

 

if ($fun=="upload")

{

include 'imageupload.php';

}

 

 

when i click upload it directs it to index.php?variable=P8&fun=upload but nothing shows up on screen

if u need more details plz ask 

 

cheers matt

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A bit confused on what your asking, hope this helps.

 

Mind putting it in [*PHP] tags to make it easier to read?

 

if ($page=="P8"&$view>0)

 

Shouldn't that be this:

 

if ($page=="P8" && $view>0)

 

Also, to display the image, wouldn't you need to call it via header?

 

header("Content-type:image/jpeg");

 

<?php
if ($_FILES)
{
$username = $_SESSION['user'];
$date =time();
$name = $_FILES["myfile"]["name"];
$type = $_FILES["myfile"]["type"];
$size = $_FILES["myfile"]["size"];
$temp = $_FILES["myfile"]["tmp_name"];
$error = $_FILES["myfile"]["error"];
$hs=$_POST['High Score']; 
$g=$_POST['Glitch']; 
$f=$_POST['Funny'];
$o=$_POST['Other']; 

$tags = new Array();
foreach($_POST['tag'] as $tag){
   if($tag){
       tags[] = $tag;
   }
}
$tag = implode(',',$tags);

if ($error > 0 )
   die("Error uploading file! Code $error.");
   else
   {
      if ($type =="image/jpeg")
         {
         include 'connect.inc';
         move_uploaded_file($temp,"uploaded/".$name);
         mysql_query("INSERT INTO images VALUES('','$name','','$username','$date','0','0','0','0','0','0','0','0')");
	$uploadreport='1';
	header("Content-type:image/jpeg");

         
         }   
      else
         {
         }

   }
}
else 
{
}

?>

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Also:

 

echo "<table class=roung bgcolor='#000000'><tr><TD><img src='uploaded/". $li2[picname] ."' width='760' height='540'></td></tr></table>";

 

Use that instead of

 

echo "<table class=roung bgcolor='#000000'><tr><TD><img src=uploaded/$li2[picname] width='760' height='540'></td></tr></table>";

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