mellis95 Posted May 18, 2011 Share Posted May 18, 2011 I am attempting to use JSON.parse for my first time today and I am having trouble figuring out what is going on. I have the following PHP code: while ($row = $query->fetch(PDO::FETCH_ASSOC)) { $dataArray[] = $row; } echo json_encode($dataArray); Which passes the following data to the client (viewed with Chrome Developer Tools): [{"coord":"23","data":"PATIENT NAME"},{"coord":"127","data":"PATIENT NAME"}] I have the following javascript code (snippet) to process the JSON: if(httpObject.readyState == 4) { if (httpObject.status == 200) { x = JSON.parse(httpObject.responseText); alert(x); } } The alert I get is: [object Object],[object Object] I have been on Google for quite a while trying to figure this out, and everything that I have read says that the following code should just work: x = JSON.parse(httpObject.responseText); alert(x.coord); If I try to access the array key (x.coord OR x.coord[0]) I get "undefined". What am I missing here? I bet it is something simple. (It usually is...) Thanks in advance for the help. Matt Link to comment https://forums.phpfreaks.com/topic/236787-jsonparse-not-working-as-i-expect/ Share on other sites More sharing options...
KevinM1 Posted May 18, 2011 Share Posted May 18, 2011 Have you tried alert(x[0].coord); ? Link to comment https://forums.phpfreaks.com/topic/236787-jsonparse-not-working-as-i-expect/#findComment-1217230 Share on other sites More sharing options...
requinix Posted May 18, 2011 Share Posted May 18, 2011 x is an array so the first thing you need is a numeric offset like x[0]. That value is an object. x will mimic the $dataArray you had in your PHP code. If you would type $dataArray[0]["coord"] in PHP then you would use x[0]["coord"] in Javascript. (But because x[0] is an object, x[0].coord works as well.) Link to comment https://forums.phpfreaks.com/topic/236787-jsonparse-not-working-as-i-expect/#findComment-1217233 Share on other sites More sharing options...
mellis95 Posted May 18, 2011 Author Share Posted May 18, 2011 WOW. I knew it would be something easy. Thank you for the help. x[0].coord is just what I needed. Matt Link to comment https://forums.phpfreaks.com/topic/236787-jsonparse-not-working-as-i-expect/#findComment-1217237 Share on other sites More sharing options...
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