super easy problem involving simple math functions

[silverglade]

I have no clue what is going on. It is driving me insane so I am trying the forum. The below code is self explanatory, and I posted my sample output after the code. Any help greatly appreciated. thank you.

 

 

here is the code

 

 

 

<?php	

       echo "<br /> Now for some math!!<br />";
   $int1 = 2;
   $int2 = 3;



        echo "<br /> \$int2 + \$int1 = ".$int2 + $int1. " .";

//subtracting

echo "<br /> \$int2 -  \$int1 = ".$int2 - $int1. " .";

//multiply

echo " <br /> \$int1 X \$int2 = ".$int1 * $int2." .";

//divide

echo "<br /> \$int2 divided / by \$int1 = ".$int2 / $int1. " .";

//remainder or modulus operator

echo "<br /> \$int2 remainder of \$int1 = ". $int2 % $int1. " .";
       ?>

       Sample output is this:

Now for some math!!
2 .-2 .
$int1 X $int2 = 6 .
$int2 divided / by $int1 = 1.5 .
$int2 remainder of $int1 = 1 . 

 

 

[spiderwell]

telling us the values of $int1 and $int2 might help or that self explanatory too 

[silverglade]

sorry i just added that

[spiderwell]

putting ($int2-$int1) did it for me same on the +

[Pikachu2000]

Enclose the math operations in parentheses to force the calculation to be performed before the value is echoed.

 

<?php
echo "<br /> Now for some math!!<br />";
$int1 = 2;
$int2 = 3;
echo "<br /> \$int2 + \$int1 = " . ($int2 + $int1);

//subtracting
echo "<br /> \$int2 -  \$int1 = " . ($int2 - $int1);

//multiply
echo " <br /> \$int1 X \$int2 = " . ($int1 * $int2);

//divide
echo "<br /> \$int2 divided / by \$int1 = " . ($int2 / $int1);

//remainder or modulus operator
echo "<br /> \$int2 remainder of \$int1 = " . ($int2 % $int1);
?>

[silverglade]

thank you so much spiderwell and Pikachu2000. This PHP for dummies book is not too good. In my book they were not inside parenthesis. It was strange that it worked for some without the parenthesis, but with + and - it didn't . So when I added () to the + and - terms, it worked!! You both  preserved my SANITY!! LOL. so thanks.