Different cases of a function

[etrader]

I have a simple function reading a two-component array as

function arr($word) {
include 'array1.php";
echo $something[$word];
}

 

How I can make a condition for this function to load different array files as array1.php or array2.php or array3.php. The name of file comes from a string.

[JonnoTheDev]

<?php
function arr($word, $include) {
include_once($include);
echo $something[$word];
}


arr('test', 'array1.php');
?>

[etrader]

Thanks, but I do not want to add the second variable into the function, since the function is widely used in the text. I get the string from url as

 

$q=$_GET[[$q];

 

now I want to include a given file for each value of $q. The text frequently contains $arr('something'). I want to display different message by $arr('something') depending on the value of $q.

[phpSensei]

OP you ment like this?

<?php

	function arr($word){

		foreach($files as $file){

			include($file);

		}
	}

	$files = array('array1.php','$array2.php','array3.php');
                arr($files);

?>

 

[phpSensei]

or did you mean this

 

<?php
$q = $_GET['q'];

function arr($word){

switch($word){

	case 'something1':
		include('array1.php');
	break;

	case 'something2':
		include('array2.php');
	break;	

}

}

arr($q);

?>

[etrader]

EXACTLY! I was thinking of switch but I was not sure if I can use it within a function.

 

Thanks a million

[etrader]

Sorry, but it did not resolve the issue. You defined the case by "something", but I want to define it by $q. For example, $q can be "modern" or "classic"; I want to include modern.php or classic.php

 

Indeed, my problem is how to bring $q into the function.

[phpSensei]

Etrader, the script can't guess what to include, you to tell it to include based on certain predefined values..

 

otheriwse the only thing you can do is

 

include($q);

 

 

[etrader]

Yes, but how I can bring $q which is a string into a function. My main problem is that. How to use $q inside function.

[JonnoTheDev]

The variable name used as a function parameter will take the value of whatever is passed into it

 

<?php

function arr($word) {
switch($word) {
  case 'modern':
   include('array1.php');
  break;
  case 'classic':
   include('array2.php');
  break;
}
}

$q = $_GET['q'];
arr($q);
?>

[etrader]

Let me clarify what I need

 

<?php
$q = $_GET['q'];

function arr($word) {
switch($q) {
  case 'modern':
   include('modern.php');
  break;
  case 'classic':
   include('classic.php');
  break;
}
}

arr($word);
?>

 

My problem is how to make switch for $q inside a function for $word.

[trq]

You'll need to pass $q into the function. Not that doing so makes any sense in this context. Tell us, why are you passing $word into your function and then not using it?

[etrader]

I use $word. Actually, the array file has a structure of

$term = array(
"word1" => "modern1",
"word2" => "modern2"
);

 

and function will be

function arr($word) {
switch($q) {
  case 'modern':
   include('modern.php');
  break;
  case 'classic':
   include('classic.php');
  break;
}
echo $term[$word];
}

 

I want to use arra('something') in the text by reading corresponding array file depending on the value of $q.

[trq]

Sorry but nothing in your last reply made any sense.

[trq]

And now you have introduced yet another non-existent variable into your function. You might want to take a look at functions.

[etrader]

I get $q by $q = $_GET['q'];

 

but I am looking for a way to bring it into the function to make the switch based on the value of $q

[phpSensei]

edit: The codes i provided did that.

[etrader]

Thanks phpSensei, but switch in your code works with $word not $q

I want to switch based on the value of $q

The problem is that $q is meaningless within function

[trq]

As has been said (and covered in the link I provided you) you will need to pass $q into the function. What part of that do you not understand?

[KevinM1]

Okay, time for a crash course in functions:

 

The first thing you need to know is that functions have their own scope.  This means that whatever is going on outside of the function will NOT be present inside the function.  At least, not unless you explicitly pass those exterior values into the function.

 

How are values passed into a function?  The correct way to do it is to use the function's argument list.  What is the argument list?

 

Functions have a signature.  The signature contains the function name and argument list.  You may have looked at the PHP manual and seen something like:

 

function name($arg1, $arg2)

 

The part within parentheses is the argument list.

 

So, if you need to use $q, you need to pass it into your function:

 

function arr($q, $word) // <-- function definition - blueprint for the function, NOT code that executes immediately
{ 
   /*
      do stuff with $q and $word
   */
}

$q = $_GET['q'];

arr($q, $word); // <-- function invocation, where arr finally runs, using the values you passed in

[phpSensei]

YAY Crash course, they are my favorite, its like an unexpected sexy party.

[etrader]

Thanks Nightslyr! You are an excellent teacher and I learned a lot. However, it did not resolve my issue. In this case, I need to include $q in $arr() within the text. I try to keep the format of $arr('some words').

 

I was looking for a trip to bring the string ($q) into the function; but it seems it is not possible. Maybe it is better to put three functions within the switch cases.

[trq]

You could drag the variable in via the global keyword but this completely breaks the encapsulation provided by the function in the first place.

 

In other words, if this is really what you want, don't use a function.

[KevinM1]

Thanks Nightslyr! You are an excellent teacher and I learned a lot. However, it did not resolve my issue. In this case, I need to include $q in $arr() within the text. I try to keep the format of $arr('some words').

 

I was looking for a trip to bring the string ($q) into the function; but it seems it is not possible. Maybe it is better to put three functions within the switch cases.

 

Maybe you should give us a clear idea as to what you're trying to do.  All I can gather is that you want $q to come in from the address bar, and you want to use it as a switch to do something.  The rest has been a series of "That's not what I'm trying to do."