Jump to content

blocks of 26 numbers every 364

lanu

By lanu
in PHP Coding Help

 Share

Recommended Posts

lanu Newbie

lanu

Posted
Posted

I'm creating an alternative calendar system(non-gregorian)

and so I need to know some basic math to figure some of this out and how to express it in php.

 

the calendar year is 364 days long and it is split into 14 months that are 26 days long each.

I have create a script that determines which day of 26 no problem, but getting the month is proving difficult.

 

My code I'm using to display the content for each of the 26 days is as follows:

 

<?php if ($beyondportal % 26 == $day1 || abs($beyondportal) % 26 == $day1){ ?>

It's day 1

<?php } ; ?>
<?php if ($beyondportal % 26 == $day2 || abs($beyondportal) % 26 == $day2){ ?>

It's day 2

<?php } ; ?>

 

etc... up to 26

 

here is the code that gives $beyondportal and the day variables their values

 

<?php
// gets todays date and compares it to 11.11.11, if its positive days get a certain set of values, if negative they get another
$elvenportal = mktime(11,11,11,11,11,2011);
$now = mktime(11,11,11,date("m"),date("d"),date("y"));
$late = date("H");
if ($late < 5) {$now = mktime(11,11,11,date("m"),date("d")-1,date("y"));};
if ($_POST["dayz"] != "" ){
if ($_POST["month"] != "" ){
if ($_POST["year"] != "" ){
$now = mktime(11,11,11,$_POST["month"],$_POST["dayz"],$_POST["year"]);
};};};

$day1 = 22;$day2 = 23;$day3 = 24;$day4 = 25;$day5 = 0;$day6 = 1;$day7 = 2;$day8 = 3;$day9 = 4;$day10 = 5;$day11 = 6;$day12 = 7;$day13 = 8;$day14 = 9;$day15 = 10;$day16 = 11;$day17 = 12;$day18 = 13;$day19 = 14;$day20 = 15;$day21 = 16;$day22 = 17;$day23 = 18;$day24 = 19;$day25 = 20;$day26 = 21;$cycle5=0;$cycle6=1;$cycle7=2;$cycle8=3;$cycle9=4;$cycle10=5;$cycle11=6;$cycle12=7;$cycle13=8;$cycle14=9;$cycle1=10;$cycle2=11;$cycle3=12;$cycle4=13;

if($now < $elvenportal){
$day1 = 4;$day2 = 3;$day3 = 2;$day4 = 1;$day5 = 0;$day6 = 25;$day7 = 24;$day8 = 23;$day9 = 22;$day10 = 21;$day11 = 20;$day12 = 19;$day13 = 18;$day14 = 17;$day15 = 16;$day16 = 15;$day17 = 14;$day18 = 13;$day19 = 12;$day20 = 11;$day21 = 10;$day19 = 12;$day22 = 9;$day23 = 8;$day24 = 7;$day25 = 6;$day26 = 5;
$cycle5=0;$cycle6=13;$cycle7=12;$cycle8=11;$cycle9=10;$cycle10=9;$cycle11=8;$cycle12=7;$cycle13=6;$cycle14=5;$cycle1=4;$cycle2=3;$cycle3=2;$cycle4=1;
};

$offset = $now-$elvenportal;
$beyondportal = FLOOR($offset/60/60/24) ;

?>

 

Now I tried to do a similar thing for the cycles like so:

 

<?php if ($beyondportal % 364 == $cycle1  || abs($beyondportal) % 364 == $cycle1){ ?>
<h4>Cycle 1</h4>
<?php } ; ?>

<?php if ($beyondportal % 364 == $cycle2  || abs($beyondportal) % 364 == $cycle2){ ?>
<h4>Cycle 2</h4>
<?php } ; ?>

etc... up to 14

 

but this seems not to be the right approach

 

any help would be really great thank you all

 

 

Link to comment
https://forums.phpfreaks.com/topic/254139-blocks-of-26-numbers-every-364/
Share on other sites
lanu Newbie

lanu

Posted
  • Author
Posted

sorry about that here's the code

 

I'm creating an alternative calendar system(non-gregorian)

and so I need to know some basic math to figure some of this out and how to express it in php.

 

the calendar year is 364 days long and it is split into 14 months that are 26 days long each.

I have create a script that determines which day of 26 no problem, but getting the month is proving difficult.

 

My code I'm using to display the content for each of the 26 days is as follows:

 

<?php if ($beyondportal % 26 == $day1 || abs($beyondportal) % 26 == $day1){ ?>
It's day 1
<?php } ; ?>
<?php if ($beyondportal % 26 == $day2 || abs($beyondportal) % 26 == $day2){ ?>
It's day 2
<?php } ; ?>

 

etc... up to 26

 

here is the code that gives $beyondportal and the day variables their values

 

<?php
// gets todays date and compares it to 11.11.11, if its positive days get a certain set of values, if negative they get another
$elvenportal = mktime(11,11,11,11,11,2011);
$now = mktime(11,11,11,date("m"),date("d"),date("y"));
$late = date("H");
if ($late < 5) {$now = mktime(11,11,11,date("m"),date("d")-1,date("y"));};
if ($_POST["dayz"] != "" ){
if ($_POST["month"] != "" ){
if ($_POST["year"] != "" ){
$now = mktime(11,11,11,$_POST["month"],$_POST["dayz"],$_POST["year"]);
};};};

$day1 = 22;$day2 = 23;$day3 = 24;$day4 = 25;$day5 = 0;$day6 = 1;$day7 = 2;$day8 = 3;$day9 = 4;$day10 = 5;$day11 = 6;$day12 = 7;$day13 = 8;$day14 = 9;$day15 = 10;$day16 = 11;$day17 = 12;$day18 = 13;$day19 = 14;$day20 = 15;$day21 = 16;$day22 = 17;$day23 = 18;$day24 = 19;$day25 = 20;$day26 = 21;$cycle5=0;$cycle6=1;$cycle7=2;$cycle8=3;$cycle9=4;$cycle10=5;$cycle11=6;$cycle12=7;$cycle13=8;$cycle14=9;$cycle1=10;$cycle2=11;$cycle3=12;$cycle4=13;

if($now < $elvenportal){
$day1 = 4;$day2 = 3;$day3 = 2;$day4 = 1;$day5 = 0;$day6 = 25;$day7 = 24;$day8 = 23;$day9 = 22;$day10 = 21;$day11 = 20;$day12 = 19;$day13 = 18;$day14 = 17;$day15 = 16;$day16 = 15;$day17 = 14;$day18 = 13;$day19 = 12;$day20 = 11;$day21 = 10;$day19 = 12;$day22 = 9;$day23 = 8;$day24 = 7;$day25 = 6;$day26 = 5;
$cycle5=0;$cycle6=13;$cycle7=12;$cycle8=11;$cycle9=10;$cycle10=9;$cycle11=8;$cycle12=7;$cycle13=6;$cycle14=5;$cycle1=4;$cycle2=3;$cycle3=2;$cycle4=1;
};

$offset = $now-$elvenportal;
$beyondportal = FLOOR($offset/60/60/24) ;

?>

 

Now I tried to do a similar thing for the cycles like so:

 

<?php if ($beyondportal % 364 == $cycle1  || abs($beyondportal) % 364 == $cycle1){ ?>
<h4>Cycle 1</h4>
<?php } ; ?>

<?php if ($beyondportal % 364 == $cycle2  || abs($beyondportal) % 364 == $cycle2){ ?>
<h4>Cycle 2</h4>
<?php } ; ?>

 

etc... up to 14

 

but this seems not to be the right approach

 

any help would be really great thank you all

Zane Prolific Member

Zane

Posted
Posted

Wouldn't something like this be a little more efficient?

$days = range(1, 364);
$months = array_chunk($days, 26);

$currentMonth = 0;
$currentDay = 253;

foreach ($months as $month => $daylist) {
$checkMonth = array_search ($currentDay, $daylist);
if (  $checkMonth !== false) { 
	$currentMonth = key($month) + 1;
	break 1;
}
}
?>

kicken Prolific Member

kicken

Posted
Posted

Wouldn't something like this be a little more efficient?

 

Than a simple modulus and division?  Not likely.

 

Running loop method: Method ran in 1.3520817756653 seconds

int(10)
int(20)
Running math method: Method ran in 0.061004877090454 seconds

int(10)
int(20)

 

when performing 100,000 iterations.

 

lanu Newbie

lanu

Posted
  • Author
Posted

This almost works for me but I'm really unsure about the math part:

<?php

$zeropoint = mktime(11, 11, 11, 06, 29, 2011);  // zero date has been moved 135 days earlier to june 29th,2011 - cycle 1, day 1 -  the new year of the calendar to simplify this 
$now = mktime(11,11,11,date("m"),date("d"),date("y")); // gets todays date
$diff = $now - $zeropoint; // do i need to do another condition incase $now is less than zeropoint or will this work? 
$cycle = $diff % 364 ; // no idea what the math is supposed to be to determine which of the 14 cycles we are currently in based on the difference between $zeropiont and $now
$day = $diff % 26 ; // no idea what the math is supposed to be to determine which of the 26 days we are currently in based on the difference between $zeropiont and $now

echo 'Cycle '.$cycle.' ';
echo 'Day: '.$day.' ';
?>

 

Thank you all so much for your help it is greatly appreciated and encouraging!

kicken Prolific Member

kicken

Posted
Posted 

$diff = $now - $zeropoint; // do i need to do another condition incase $now is less than zeropoint or will this work?

 

You can wrap in in abs() to ensure it is positive.

 

$cycle = $diff % 364 ; // no idea what the math is supposed to be to determine which of the 14 cycles we are currently in based on the difference between $zeropiont and $now

 

$diff is in # of seconds, so your statement is not going to work.  It's also not correct, look at what I did above.  The cycles is gathered via integer division.  Since your interested in days, you'd be best served by converting $diff to days first.

$days = $diff/(60*60*24);
$cycle = intval($days / 26)+1; //26 days in your cycles.  +1 to make it 1-14 rather than 0-13

 

The current day you get via the modulus operator which returns the remainder of a division operation

$day = $diff % 26 + 1; //26 days in the cycle.  +1 to make it 1-26 rather than 0-25

 

Modulus returns the number value past the last evenly divisible number.

 

So say your $diff is 176 (days). 176/26 = 6.769

So we drop the decimals and multiple the integer with 26, to get 26*6 = 156

Then we take that and subtract it from 176, for: 176-156=20

 

So modulus will return 20.

 

 

So for $diff=176 (days) we get:

$cycle = intval(176/26)+1 = 7;

$day = 176 % 26 + 1  = 21;

 

So you are on cycle 7, day 21.

 

lanu Newbie

lanu

Posted
  • Author
Posted

almost got it now. it works great going forward but backward has some issues.

 

if beyond portal is a date from the past we run into a problem because 1 day BEFORE 0 is actually DAY 26 where as 1 day after is DAY 2.

My problem is I'm getting DAY 2 when it is supposed to be getting DAY 26 and likewise any dates before 11.11.11 are being counted wrong.

 

any suggestions? here's the code:

 


$elvenportal = mktime(11,11,11,11,11,2011);
$now = mktime(date("H"),date("i"),date("s"),date("n"),date("j"),date("Y"));
$offset = $now - $elvenportal;
$beyondportal = abs($offset/(60*60*24));
$beyondportal = $beyondportal+108; // start of new year is 108 days before 11.11.11
$day = $beyondportal % 26 + 1; //26 days in the cycle.  +1 to make it 1-26 rather than 0-25 
$cycle = intval($beyondportal / 26) % 14+1; //26 days in your cycles.  +1 to make it 1-14 rather than 0-13

// do I need a conditional statement to calculate differently for negative numbers?

 

ANy help would be greatly appreciated. thanks so much!

lanu Newbie

lanu

Posted
  • Author
Posted

I got it to work, though not the most elegant solution, it does the job for my purposes.

I have given each of the days different values in the case that its a date earlier than 11.11.11 so the days and cycles match up forwards and backwards.

Thanks again for all your help I LOOOOVE PHP FREAKS!

 

<?php
// THEE AURON CALCULATOR

$elvenportal = mktime(11,11,11,11,11,2011);
$now = mktime(date("H"),date("i"),date("s"),date("n"),date("j"),date("Y"));
$late = date("H");
$theeday = date("d")-1;
if ($late < 7) {$now = mktime(11,11,11,date("n"),$theeday,date("Y"));};
if ($_POST["dayz"] != "" ){
if ($_POST["month"] != "" ){
if ($_POST["year"] != "" ){
$now = mktime(11,11,11,$_POST["month"],$_POST["dayz"],$_POST["year"]);
};};};

$offset = $now - $elvenportal;
$beyondportal = abs($offset/(60*60*24));


$beyondportal = abs($beyondportal+108);
$day = abs($beyondportal % 26 + 1); //26 days in the cycle.  +1 to make it 1-26 rather than 0-25 
$cycle = abs(intval($beyondportal / 26) % 14+1); //26 days in your cycles.  +1 to make it 1-14 rather than 0-13


if ($elvenportal > $now){
if ($day == 6){$day = 4;}
else if ($day == 7){$day = 3;}
else if ($day == {$day = 2;}
else if ($day == 9){$day = 1;}
else if ($day == 10){$day = 26;}
else if ($day == 11){$day = 25;}
else if ($day == 12){$day = 24;}
else if ($day == 13){$day = 23;}
else if ($day == 14){$day = 22;}
else if ($day == 15){$day = 21;}
else if ($day == 16){$day = 20;}
else if ($day == 17){$day = 19;}
else if ($day == 18){$day = 18;}
else if ($day == 19){$day = 17;}
else if ($day == 20){$day = 16;}
else if ($day == 21){$day = 15;}
else if ($day == 22){$day = 14;}
else if ($day == 23){$day = 13;}
else if ($day == 24){$day = 12;}
else if ($day == 25){$day = 11;}
else if ($day == 26){$day = 10;}
else if ($day == 1){$day = 9;}
else if ($day == 2){$day = 8;}
else if ($day == 3){$day = 7;}
else if ($day == 4){$day = 6;}
else if ($day == 5){$day = 5;}
else if ($day == 6){$day = 4;};

if ($beyondportal > 4){
if ($cycle == 1){$cycle = 8;}
else if ($cycle == 2){$cycle = 7;}
else if ($cycle == 3){$cycle = 6;}
else if ($cycle == 4){$cycle = 5;}
else if ($cycle == 5){$cycle = 4;}
else if ($cycle == 6){$cycle = 3;}
else if ($cycle == 7){$cycle = 2;}
else if ($cycle == {$cycle = 1;}
else if ($cycle == 9){$cycle = 14;}
else if ($cycle == 10){$cycle = 13;}
else if ($cycle == 11){$cycle = 12;}
else if ($cycle == 12){$cycle = 11;}
else if ($cycle == 13){$cycle = 10;}
else if ($cycle == 14){$cycle = 9;};
};

/* if ($day == 1){$day = 5;}
else if ($day == 2){$day = 4;}
else if ($day == 3){$day = 3;}
else if ($day == 4){$day = 2;}
else if ($day == 5){$day = 1;}
else if ($day == 6){$day = 26;}
else if ($day == 7){$day = 25;}
else if ($day == {$day = 24;}
else if ($day == 9){$day = 23;}
else if ($day == 10){$day = 22;}
else if ($day == 11){$day = 21;}
else if ($day == 12){$day = 20;}
else if ($day == 13){$day = 19;}
else if ($day == 14){$day = 18;}
else if $day == 15){$day = 17;}
else if ($day == 16){$day = 16;}
else if ($day == 17){$day = 15;}
else if ($day == 18){$day = 14;}
else if ($day == 19){$day = 13;}
else if ($day == 20){$day = 12;}
else if ($day == 21){$day = 11;}
else if ($day == 22){$day = 10;}
else if ($day == 23){$day = 9;}
else if ($day == 24){$day = 8;}
else if ($day == 25){$day = 7;}
else if ($day == 26){$day = 6;}
else{echo "";}

if ($cycle = 5){$cycle = 1;}
else if ($cycle = 6){$cycle = 14;}
else if ($cycle = 7){$cycle = 13;}
else if ($cycle = {$cycle = 12;}
else if ($cycle = 9){$cycle = 11;}
else if ($cycle = 10){$cycle = 10;}
else if $cycle = 11){$cycle = 9;}
else if ($cycle = 12){$cycle = 8;}
else if ($cycle = 13){$cycle = 7;}
else if ($cycle = 14){$cycle = 6;}
else if ($cycle = 1){$cycle = 5;}
else if ($cycle = 2){$cycle = 4;}
else if ($cycle = 3){$cycle = 3;}
else if ($cycle = 4){$cycle = 2;}
else{echo "";}*/
};


?>

Pikachu2000 Prolific Member

Pikachu2000

Posted
Posted

Just a couple of notes, if you're interested. For the $now variable, you don't need to call date() 6 times within mktime(). It's a relatively slow function to begin with; you can simply use $now = time().

 

For the two stacks of if/elseif conditionals, you might find it cleaner to use lookup arrays to pull the values from. There's nothing particularly wrong with the way you have it now; it's just a thought in case you want less lines of code.

$lookup_days = array( 1 => 9, 8, 7, 6, 5, 4, 3, 2, 1, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10 );

if ($elvenportal > $now){
$day = $lookup_days[$day];
}

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
 Share
Go to topic listing
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.