How do I show the odds?

[Monkuar]

$card1 = rand(1,3);
$card2 = rand(1,3);

/// check money win ////////
if($card1 == "1" && $card2 == "1" ){
echo "You won 100$?";
exit;
mysql_query("UPDATE card SET money='$win_money' WHERE name='$name'");
}

 

My code works wonderfully

 

prob tho

how can I show the odds of winning out of 100 to my suer?

[spiderwell]

google found me this http://gwydir.demon.co.uk/jo/probability/calcdice.htm#cond1

 

and thats on dice, but i figured dice are 6 and yours are 3, so i came up with 1 in 6, as each one has a 1 in 3 chance

 

'm not to good on odd calculating but the link might help a bit

[ManiacDan]

It's 1 in 9.

 

Basic statistics have nothing to do with  PHP. 

 

Also, this code has an exit() call BEFORE the mysql_query, that query will never run.  There's also a random closing curly brace.

[Pikachu2000]

If you have 3 picks from a pool of 36 numbers, and none of the numbers can repeat, the chances are 36*(36-1)*(36-2), or 1 in 42840. How to calculate the chances if the order of the numbers picked is required to match the order of the numbers drawn, I don't know.

[ManiacDan]

Pika.......what?  He has two numbers, 1-3 each.  And he wants to know the odds of getting a 1,1. 

[Pikachu2000]

Oh yeah, I kind of glossed over the code, thinking it was the same code from the other thread, with 3 non-repeating numbers from a pool of 36.

 

I are sorry : (

[ManiacDan]

Ok, at least you're not crazy.

[Pikachu2000]

Oh, that doesn't mean I'm not crazy.

[Monkuar]

Im still confused

 

$card1 = rand(1,4);
$card2 = rand(1,4);
if ($ibforums->input['id'] == "1"){
if($card1 == "1" && $card2 == "1"){

 

if my stuff is 1 in 4 chances

 

and it both has to equal the same "1"

 

that would be 25% divided by 2

 

which is

12.5% of winning right?

 

[ManiacDan]

Again, basic statistics have nothing to do with PHP.  You want to study basic probability.

 

The probability of the first number being 1 is 1/4.  The probability of the second number being 1 is also 1/4.  You multiply the odds together to get your answer: 1/4 x 1/4 = 1/16, or 6.25%

 

 

 

 

[Psycho]

This should allow you to dynamically determine the odds based upon a max number.

$max_num = 4;

$card1 = rand(1, $max_num);
$card2 = rand(1, $max_num);

$odds = pow((1/$max_num), 2); //2 is the number of 'cards'