techker Posted April 2, 2012 Share Posted April 2, 2012 hey guy i doing a litle script for renting dvd's.. i got the DB OUT for rentals and employee for id of the person renting it.. So on my page account i wan't to list the rented dvd's from the employee need to check the OUT database and the Location database for the movie title and pics.. i got this but i got a syntax error.. $query = "SELECT OUT.Employer,OUT.DVD_ID, Location.L_ID ". "FROM OUT, Location ". "WHERE OUT.DVD_ID = Location.L_ID AND OUT.Employer = $Account"; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OUT, Location WHERE OUT.DVD_ID = Location.L_ID AND OUT.Employer = techker' at line 1 Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/ Share on other sites More sharing options...
smerny Posted April 2, 2012 Share Posted April 2, 2012 the error is because "out" is a reserved word in mysql. best thing to do would be to not use reserved words for names of tables/columns here is a list of reserved words for reference: http://dev.mysql.com/doc/refman/5.5/en/reserved-words.html Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333609 Share on other sites More sharing options...
techker Posted April 2, 2012 Author Share Posted April 2, 2012 ahh...lol thx Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333630 Share on other sites More sharing options...
techker Posted April 2, 2012 Author Share Posted April 2, 2012 last thing..now i get Unknown column 'Techker' in 'where clause' i think it's in my were clause?im missing something no? WHERE OUT.DVD_ID = Location.L_ID AND OUT.Employer = $Account"; Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333650 Share on other sites More sharing options...
Jessica Posted April 2, 2012 Share Posted April 2, 2012 You need single quotes around a string. I assume $Account = 'Techker'. It thinks you're looking for a column since it's not within quotes. Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333651 Share on other sites More sharing options...
techker Posted April 2, 2012 Author Share Posted April 2, 2012 wow fast.. will this formula do what i need?cause now im getting zero output from it.. Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333652 Share on other sites More sharing options...
cpd Posted April 2, 2012 Share Posted April 2, 2012 You can use reserved words, just make sure you wrap them in slanted apostrophes. There's no need for you to have a full stop at the end of each line either. $sql = "SELECT `OUT`.`Employer`,`OUT`.`DVD_ID`, `Location`.`L_ID` FROM `OUT`, `Location` WHERE `OUT`.`DVD_ID` = `Location`.`L_ID` AND `OUT`.`Employer` = '{$Account}'"; If your not getting any results ensure a result set is being returned and no errors are occurring with the mysql_errors() function. If everything's fine, you probably don't have any results matching that query. Moreover, with joins such as these you can easily get ambiguity so be careful. Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333669 Share on other sites More sharing options...
techker Posted April 2, 2012 Author Share Posted April 2, 2012 ok cool thx! Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333675 Share on other sites More sharing options...
techker Posted April 2, 2012 Author Share Posted April 2, 2012 still doesnt work..fill the database.. so my goal is to check the rentals done by the loggin in user. so in rentals is have R_ID DVD_ID Employee LP Date then i want to go in the Locations(dvd's) and get the DVD info that he rented.(DVD_ID) L_ID Titre Date Prix Categorie Image Status UPC so basically when he goes to the account page it shows his rented movies.. Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333680 Share on other sites More sharing options...
cpd Posted April 2, 2012 Share Posted April 2, 2012 Re-read my post and try doing a bit of debugging as described. Quote Link to comment https://forums.phpfreaks.com/topic/260200-left-join/#findComment-1333721 Share on other sites More sharing options...
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