Php commad using shell

[sandy1028]

Please tell me how to call, getimagesize() in exec command.

http://www.example.com/images!/logos/ps_logo2.png

I am using the linux enviroment. If the uRL has "!" symbol, it prints event not found.

 

Please tell me how to avoid this.

 

[trq]

Your going to need to be clearer with your description.

 

You can write a script that calles getimagesize() and then call that script from the shell. But getimagesize() isn't a shell commend so it cannot be called directly.

[sandy1028]

When ran the below line on command prompt,

 

php -r "print_r(getimagesize('http://www.example.com/images!/logos/ps_logo2.png'));"

-bash: !/logos/ps_logo2.png': event not found

 

To avoid this wrapped in the sahll script.

 

#!/bin/bash

php -r "print_r(getimagesize('http://www.example.com/images!/logos/ps_logo2.png'));"

 

can you please tell me, how can we avoid this in php script.

[kicken]

You can just reverse the quotes so you encase the php code in single quotes.

 

php -r 'print_r(getimagesize("http://www.example.com/images!/logos/ps_logo2.png"));'

 

Then bash won't interpret the ! as special character.