Need to remove white sapces with regular expression

[suresh_kamrushi]

I have a string like below:

%s% % % sent you a Mystery Gift with

I want to remove white spaces between % (percent) sign only by using regular expression so that string will look like

%s%%% sent you a Mystery Gift with

 

Thanks in Advance

[MMDE]

nvm

[Christian F.]

Why not just use str_replace ()? RegExp seems to be a bit overkill for something as simple as this.

[MMDE]

Why not just use str_replace ()? RegExp seems to be a bit overkill for something as simple as this.

So what do you suggest the search string to be, and the replacement?

 

echo str_replace('% %', '%%', '%s% % % sent you a Mystery Gift with');

 

Was my original thought, but then I noticed it prints this:

%s%% % sent you a Mystery Gift with

 

I guess you can do:

echo str_replace('% ', '%', '%s% % % sent you a Mystery Gift with');

[Christian F.]

No need to make it more complex than it has to be: str_replace (' %', '%', $string)

[MMDE]

No need to make it more complex than it has to be: str_replace (' %', '%', $string)

Ah, yes, I came up with that probably a couple of seconds after you. xD

 

echo str_replace('% ', '%', '%s% % % sent you a Mystery Gift with');

Though I placed the space after the first %, you could choose one or both to really remove all of them.

[suresh_kamrushi]

Thanks Guys!!

With str_replace i already figure it out like this

$string = "%s% % % sent you a Mystery Gift with";
$possibleSearch = array("% %","%% %","% %%");
$possibleValue = array("%%","%%%","%%%");
$newString = str_replace($possibleSearch,$possibleValue,$string);

 

But really i need it with reg_replace function.

 

Any answer appreciated!!!

Thanks in Advance

[Christian F.]

That begs the question: Why do you think you need it as a RegExp?

 

Also, please see my last post again.

[MMDE]

Thanks Guys!!

With str_replace i already figure it out like this

$string = "%s% % % sent you a Mystery Gift with";
$possibleSearch = array("% %","%% %","% %%");
$possibleValue = array("%%","%%%","%%%");
$newString = str_replace($possibleSearch,$possibleValue,$string);

 

But really i need it with reg_replace function.

 

Any answer appreciated!!!

Thanks in Advance

We've both posted you two working codes.

If you want to use more resources, just replace str in the function name with preg, and place a / at the start and the end of the search string (pattern).