Function within function

[rem]

Hello,

Could you please point me towards the right path here?
I have a PHP5 class with multiple functions. Somehow, within those functions, there is a pattern which is repeated across the code. I thought, why not do a function to take care of the pattern and call it within the other functions whenever is needed ?

ex:
[code]<?php

Class Example {

    public $value;

    public function my_pattern() {
   
    //do something with $this->value;
    }

    public function some_other_function() {
   
    $test = new Example;
    //do something with $test->my_pattern();
  }

}
?>[/code]

I don't know what am I doing wrong but $this->value is not assigned within my_pattern() function ... My head hurts bad ... Please help  ??? :'(...

Thank you very much!

[JasonLewis]

whats with the public stuff. just do var $value; and remove the public from the start of the function. it probably wont effect anything but i find that code annoying for some reason..

now...
Instead of calling it by $test->my_pattern() from inside the function call it like $this->my_pattern()
if thats what your wanting to no.

[rem]

[quote author=ProjectFear link=topic=114514.msg465938#msg465938 date=1163156538]
whats with the public stuff. just do var $value; and remove the public from the start of the function. it probably wont effect anything but i find that code annoying for some reason..

now...
Instead of calling it by $test->my_pattern() from inside the function call it like $this->my_pattern()
if thats what your wanting to no.
[/quote]

Thanks a lot, I'll give that a try ... but that "public stuff" isn't how PHP5 handles it now?

[rem]

Yeap, it worked! Thanks a lot ProjectFear. I could swear I tried that myself and it didn't then...  Anyway, I'm sure must been screw things up somehow.

[redbullmarky]

ProjectFeat - var $value will work on both PHP4 and 5, but strictly, the correct way is to declare a var/function within a class is either public/private/protected which is the way PHP5 utilises. someone correct me if i'm wrong, but i'm pretty sure using 'var' in PHP5 throws a notice as deprecated.

[JasonLewis]

i am using PHP5 and i am user var with no troubles at all....

[roopurt18]

Using var with PHP5 will cause a warning if you have your error reporting set correctly.