$_Get['']

[Solar]

I understand the $_GET[''] function.. but I have ran into an error.

Lets say my URL is localhost.php/test.php?say=#hello

The $_GET[''] function will only take the print after the equal and before the pound sign. - Which is blank

 

My question is... What function should I use to parse after the # sign?

 

Thanks,

Steven

[xfactorr]

you can use

substr($_GET["say"], 1);

to remove # sign

[requinix]

The anchor/fragment (the thing after the #) is never sent to the server. You will never receive it ever.

 

$_GET["say"] will be empty.

[cyberRobot]

If the value needs to contain a # symbol, you could encode it:

 

<?php
print '<a href="localhost.php/test.php?say=' . urlencode('#hello') . '">Test</a>';
?>

[ManiacDan]

Also, $_GET is an array, not a function. It's a regular variable except for its scope.

[Solar]

I have decided to take a different approach to this method. After researching; everyone's reply is the same response I recieved when reviewing the PHP.net website.

Thank-you for your time, if the method was possible, it would have saved me a ton of time. But in the long run, the method I expected is not proper.

 

Thanks again,

Solar

[ManiacDan]

Just to be clear: This method works perfectly well for every non-reserved character. Characters like @, #, &, ?, /, and = are reserved for use as URL delimiters, which is why they need to be escaped. All you'd have to do is change #hello to $hello (or something else) and it would have started working. Unless you're relying on the specific behavior of jump-to-tag while also trying to get that tag in a PHP script, in which case you should know that jumping to tags on the same page never refreshes the page, so PHP never happens.