Problem Echoing Sqlsrv Results

[mrPickles]

Hello all,

 

I have a Windows Server 2008 R2 Standard 64-bit server running WAMP 2.2 along with PHP 5.3.13 and a SQL Server Enterprise 64-bit. SQLSRV is registered as a PHP stream using Microsoft Drivers 3.0 for PHP and SQL Server. The connection is made without issue and the query is working as it should, the only problem is that I haven't figured out the correct way to display what is returned by the query. Maybe you all might be able to help me out! Here's a look at a couple things I've been trying.

 

if( $conn ) {
 echo "Connection established.<br />";
}else{
 echo "Connection could not be established.<br />";
 die( print_r( sqlsrv_errors(), true));
}
$query = "SELECT top (10) docid, sequence, server, share, path, filename ";
$query .= "FROM files ";
$query .= "WHERE filename like '%2008010639029%'";
$result = sqlsrv_query($conn, $query) or die (sqlsrv_errors());  
if(sqlsrv_has_rows($result)){ echo "1 or more rows have been returned<br />";}
else
{echo "No results were found.<br />";}

while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
print_r ($row);
}

 

When that script is run the results of the query are correct it is just displayed like so:

 

Here is the other method that I'm using that gets close.

if( $conn ) {
 echo "Connection established.<br />";
}else{
 echo "Connection could not be established.<br />";
 die( print_r( sqlsrv_errors(), true));
}
$query = "SELECT top (10) docid, sequence, server, share, path, filename ";
$query .= "FROM files ";
$query .= "WHERE filename like '%2008010639029%'";
$result = sqlsrv_query($conn, $query) or die (sqlsrv_errors());  
if(sqlsrv_has_rows($result)){ echo "1 or more rows have been returned<br />";}
else
{echo "No results were found.<br />";}

while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
 $docid = sqlsrv_get_field($result, 0);
 $sequence = sqlsrv_get_field($result, 1);
 $server = sqlsrv_get_field($result, 2);
 $share = sqlsrv_get_field($result, 3);
 $path = sqlsrv_get_field($result, 4);
 $filename = sqlsrv_get_field($result, 5);

 echo "$docid" . "$sequence, " . "$server, " .
   "$share, " . "$path, " . "$filename, " . '<br />';
}

 

The result is:

 

Do you all have any suggestions? Thanks a ton for looking at this.

[Jessica]

$row is an associative array. If you want to echo docid, you'll echo $row['docid']. etc, etc.

[Barand]

As you are requesting an associative array result try

 

$docid = sqlsrv_get_field($result, 'docid');

instead of

 

$docid = sqlsrv_get_field($result, 0);

[mrPickles]

Wow thank you both for the quick replies.

 

@Jessica - When using that method I encounter the undefined index error and I think I know what you're going to say about that... use isset(). The thing is I don't know exactly what to check means as how I've tried a couple ways without success. The following code generates the error to follow.

$query = "SELECT top (10) docid, sequence, server, share, path, filename ";
$query .= "FROM files ";
$query .= "WHERE filename like '%2008010639029%'";
$result = sqlsrv_query($conn, $query) or die (sqlsrv_errors());  
if(sqlsrv_has_rows($result)){ echo "1 or more rows have been returned<br />";}
else
{echo "No results were found.<br />";}

while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
 $docid = sqlsrv_get_field($result, '0');
 $sequence = sqlsrv_get_field($result, '1');
 $server = sqlsrv_get_field($result, '2');
 $share = sqlsrv_get_field($result, '3');
 $path = sqlsrv_get_field($result, '4');
 $filename = sqlsrv_get_field($result, '5');
echo $row['DOCID'].", ". $row['SEQUENCE'].", ". $row['SERVER'].", ".
 $row['SHARE'].", ". $row['PATH'].", ".
 $row['FILENAME']."<br />";
}

 

@Barand - Using your approach:

$query = "SELECT top (10) docid, sequence, server, share, path, filename ";
$query .= "FROM files ";
$query .= "WHERE filename like '%2008010639029%'";
$result = sqlsrv_query($conn, $query) or die (sqlsrv_errors());  
if(sqlsrv_has_rows($result)){ echo "1 or more rows have been returned<br />";}
else
{echo "No results were found.<br />";}

while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
 $docid = sqlsrv_get_field($result, 'docid');
 $sequence = sqlsrv_get_field($result, 'sequence');
 $server = sqlsrv_get_field($result, 'server');
 $share = sqlsrv_get_field($result, 'share');
 $path = sqlsrv_get_field($result, 'path');
 $filename = sqlsrv_get_field($result, 'filename');
echo $row['DOCID'].", ". $row['SEQUENCE'].", ". $row['SERVER'].", ".
 $row['SHARE'].", ". $row['PATH'].", ".
 $row['FILENAME']."<br />";
}

 

And yields:

[Jessica]

Why are you doing it in all caps when your own print_r shows it clearly in lowercase?

[Barand]

And I'm curious to know if

 

echo "$docid, " . "$sequence, " . "$server, " .
       "$share, " . "$path, " . "$filename, " . '<br />';

worked after trying my suggestion.

[Jessica]

Barand, see his second screenshot.

[Barand]

Jessica, I know he tried my suggestion but then he does this

 

echo $row['DOCID'].", ". $row['SEQUENCE'].", ". $row['SERVER'].", ".
$row['SHARE'].", ". $row['PATH'].", ".
$row['FILENAME']."<br />";

 

EDIT

 

Ah yes - error message. I guess get_field isn't really what he wanted anyway. Haven't used sqlsrv since I retired.

[mrPickles]

That worked... I should have picked up on that but I typically deal with T-SQL which isn't case sensitive. Thank you both for the help, This is a nice community.