nopelken Posted November 7, 2012 Share Posted November 7, 2012 Hello, I'm very newbie at PHP level. Someone told me to ask the question here. I have made a html page, on which the user must enter his entry code. Eg:2012 / 2013 I also have a folder on the webserver with that name. When the user enters his code, I want him to show the images in the folder. There is no database relied to it. How can I show eg. image201201 and 201202 when user 1 is entering code 2012 and show image201301 and image 201302 when user is entering code 2013. Thanks in advance. Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/ Share on other sites More sharing options...
Muddy_Funster Posted November 7, 2012 Share Posted November 7, 2012 do you have any cod ein place at the moment? Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390837 Share on other sites More sharing options...
nopelken Posted November 7, 2012 Author Share Posted November 7, 2012 I only have some javascript code I tried, but nothing in php, <script type="text/javascript">var imageID=0 function ShowPicture { var code = prompt("Enter code:"); if (code == 2012) { alert('Hallo'); image1 = newImage(); image1.src = "/pict/2012/01.jpg"; image2=newimage(); image1.src = "/pict/2012/02.jpg"; } if (code == 2013) { alert('Hallo'); image1 = newImage(); image1.src = "/pict/2013/01.jpg"; image2=newimage(); image1.src = "/pict/2013/02.jpg"; } }</script></head><body onload=ToonFoto()></body>[code] That's what I tried in javascript, but doesn't work. Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390851 Share on other sites More sharing options...
Muddy_Funster Posted November 7, 2012 Share Posted November 7, 2012 well you'll need to take a stab it it first, then we can help if you need it, which you might well not. start with looking up glob() Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390854 Share on other sites More sharing options...
JonnoTheDev Posted November 7, 2012 Share Posted November 7, 2012 <?php $path_to_dir = '/path/to/images/dir/2012/'; if ($handle = opendir($path_to_dir)) { while (FALSE !== ($entry = readdir($handle))) { if ($entry != '.' && $entry != '..' && !is_dir($entry) && preg_match('/jpg|gif|png/i', $entry)) { echo "<img src=\"" . $path_to_dir . $entry . "\" />\n"; } } closedir($handle); } ?> Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390878 Share on other sites More sharing options...
AyKay47 Posted November 7, 2012 Share Posted November 7, 2012 A suggestion to the above code would be to strengthen the regex filter a little. As is, a file named jpg.exe would pass the filter. Something such as: preg_match('/^[a-z0-9]+\.(jpg|gif|png)$/i', $entry) should be fine for what you are using it for. Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390890 Share on other sites More sharing options...
nopelken Posted November 7, 2012 Author Share Posted November 7, 2012 I'm getting an error: Warning: opendir() has been disabled for security reasons on line 3 Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390895 Share on other sites More sharing options...
AyKay47 Posted November 7, 2012 Share Posted November 7, 2012 That is a hosting provider issue and you will need to contact them. Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390897 Share on other sites More sharing options...
DavidAM Posted November 7, 2012 Share Posted November 7, 2012 You could try glob as in: $ArrayOfFileNames = glob('/path/to/images/dir/2012/*.{jpg,gif,png}', GLOB_BRACE); which might not be disabled, and eliminates the need for the preg_match. Then use foreach to walk the array of files. I can't remember right off if the filenames in the array will include the full path or just the names. Also, remember glob() will return false if it does not find any files that match Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390912 Share on other sites More sharing options...
nopelken Posted November 7, 2012 Author Share Posted November 7, 2012 Where do I have to put the input box where the code is asked and so I do if (code==2012) $path_to_dir ='/path/to/images/dir/2012/' if (code==2013) $path_to_dir ='/path/to/images/dir/2013/'; Something like this ? Files are all jpg. Link to comment https://forums.phpfreaks.com/topic/270417-show-image-from-folder/#findComment-1390915 Share on other sites More sharing options...
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