Show Image If It Exists Else..

[TKO]

Hello i am tring to show $image1 if it exists and if not show $image2

This script shows $image1 but if i erase the image it just shows a broken image icon and doesnt go to $image2

any help in this would be great

 

<?php
   $image0 = $_SESSION['ls_user'];
   $image1 = "<img src=img/$image0.png>";
   $image2 = "<img src=img/default.png>";
   if ( $image1 ) {
   echo $image1;
   } else {
   echo $image2;
   }
?>

 

thank you

[Jessica]

That doesn't check if the image actually exists. You just set $image1, it will always evaluate to true. If you want to check for the file with that name, use file_exists

[TKO]

thanks for the reply

now the code only shows $image2

<?php
   $image0 = $_SESSION['ls_user'];
   $image1 = "<img src=img/$image0.png>";
   $image2 = "<img src=img/default.png>";
   if (file_exists( $image1 )) {
   echo $image1;
   } else {
   echo $image2;
   }
?>

[Pikachu2000]

You're using it wrong. Read the manual and give it another shot: file_exists

[TKO]

hmm i dont see it ??

when i test echo $image1 it shows.

the only thing i can think of is

echo "$image1";
       } else {
       echo "$image2";

 

which still shows $image2

[codefossa]

You need to use an actual path to the image. Also, to check if it exists and that it's an image all in one, you can do if (getimagesize($fn)) and it works well. (: It may be possible that some image filetypes ain't supported by it though, but all the common ones are.

 

Also, you should put {} around your variables when in a string, but you don't need to use the quotes there so it would make more sense to just echo the var.

 

PS: $fn or filename would be the path to it such as /var/www/images/mypic.jpg or if you're in /var/www already you could just do ./images/mypic.jpg but you don't use an HTML image tag.

[winningdave]

$image0 = $_SESSION['ls_user'];

$image = "img/".$image0.".png";

$image1 = "<img src=img/$image0.png>";

$image2 = "<img src=img/default.png>";

if (file_exists( $image )) {

echo $image1;

} else {

echo $image2;

}

[TKO]

wow thanks for the reply's i will try them when i get home.

Thank you

[TKO]

Thank you all for your reply's

winningdave solution worked perfect.

Thank you winningdave