Pulling Two Values

[DSTR3]

I have code that is working.

 

$('.Kitty').live("change",function(){
var LocationString = 'Lid='+ $(this).val();
   $.ajax({
    type: "POST",
    url: "ajax_area.php",
    data:  LocationString,
    cache: false,
    success: function (html) {		   
$(".Pig").html(html);

 

However; I need two values. Lid (LocationString) and Cid (CityString) How would I do this? I tried this and it doesn't work.

 

$('.Kitty').live("change",function(){
var LocationString = 'Lid='+ $(this).val();
var CityString = 'Cid='+ $(this).val();
   $.ajax({
    type: "POST",
    url: "ajax_area.php",
    data: {Lid: LocationString, Cid:CityString},
    cache: false,
    success: function (html) {		   
$(".Pig").html(html);

 

And this is the ajax_area.php file. Its grabbing Lid successfully, how is Cid added to this mix?

 

<?php
require('config.php');
if($_POST['Lid'])
{
$Lid=$_POST['Lid'];

$sql=mysql_query("SELECT tblLocations.RestID as Lid, tblAreas.AreaName as name
   FROM tblLocations INNER JOIN tblAreas ON tblLocations.AreaID = tblAreas.AreaID
   WHERE tblLocations.RestID = $Lid
   GROUP BY tblLocations.RestID, tblAreas.AreaName
   ORDER BY tblAreas.AreaName ASC");
echo '<option selected="selected">--Select Area--</option>';
while($row=mysql_fetch_array($sql))
{
echo '<option value="'.$row['Lid'].'">'.$row['name'].'</option>';
}
}
?>

 

Help is appreciated! Thank you!

[Jessica]

You have $Lid=$_POST['Lid']; and you're asking how you would get the posted value of Cid as well? ..... Did you try anything yet?

 

Regardless they'll be the same value.

var LocationString = 'Lid='+ $(this).val();
var CityString = 'Cid='+ $(this).val();

.

Edited January 18, 2013 by Jessica

[DSTR3]

Thank you. Yes I tried various things. All met with failure.! These are two different values. How do I do this? Your help is greatly appreciated. Thank you. I need two different values. Lid and Cid.

Edited January 18, 2013 by DSTR3

[Jessica]

Read the links in my signature about how to get good help. 

 

What did you try? If they are two different values, why are you assigning them from the same value?

[DSTR3]

It really doesn't matter what I tried, because nothing worked. How do I assign two different values? Thank you.

[Jessica]

With an equals sign and then two different values. 

[DSTR3]

Do you mean like this?

 

var LocationString = 'Lid='+ $(this1).val();
var CityString = 'Cid='+ $(this2).val();

 

or this?

 

]

var LocationString = 'Lid='+ $(this).val();
var CityString = 'Cid='+ $(this).va2l();

]

Edited January 18, 2013 by DSTR3

[DSTR3]

Solved!

 

$(document).ready(function()
{
$(".Doggie").change(function()
{
var LocationString ='Rid='+ $(this).val();
   $.ajax({
    type: "POST",
    url: "place_city.php",
    data: LocationString,
 cache: false,
    success: function (html) {
	    $(".Kitty").html(html);
    }
   });
});
$('.Kitty').live("change",function(){
var Rid = $('#Doggie').val(),  // This is the value of the id="Doggie" selected option
   Cid = $(this).val(); // This is the value of the id="Kitty" selected option
//alert("Rid = " + Rid + " Cid = " + Cid);
$.ajax({
    type: "POST",
    url: "place_area.php",
    data: {"Rid":Rid,"Cid":Cid},
    cache: false,
    success: function (html) {
  //alert('This is what is returned from the php script: ' + html);			
$(".Pig").html(html);
}
});
});
});