ozolinse Posted March 2, 2013 Share Posted March 2, 2013 Greetings all... I have a quick question and I'll explain it to the best of my ability in hopes of obtaining a quick answer. I have a mysql database for the website which logs 'fish catches' for an online fishing tournament I run. The original person who wrote the code is no longer able to help due to family issues thus I am trying to learn as much as I can. - I have tables for species, anglers, images, submissions (submit), regions, and teams. - Under the species table are relevant columns species_id (numerical number in system just for organization), species_name (name of fish species ex. Tuna), and a few others for region/location etc. - Under the submit table are columns length, submit_id, angler, team_id, species_id, date, image...water...etc Since this particular page we are discussing is the 'all-time records' page, the script was 'grouped' and joined with the query. My issue is the current records are fully working like always have been but are being displayed in order of species_id where as I need it to be displayed by species_name in alphabetical order instead. Here is part of the current code which I need to change and can't figure it out to get it to display in order of species_name... I've learned quite a bit of php but have not come familar with grouping and joining. Any help would be greatly appreciated. I can provide the online address of the page for reference if needed. function get_species() { global $species_id; global $speciesname; $query_a = "SELECT species_name FROM species WHERE species_id='$species_id'"; $results_a = mysql_query($query_a) or die(mysql_error()); $row_a = mysql_fetch_array($results_a); extract ($row_a); $speciesname = $species_name;} //Query for records region 1 $records1 = "SELECT angler ,team_id ,dt.species_id ,length ,image ,yyyy ,mm ,dd FROM submit join (SELECT species_id, max(length) as mlength FROM submit WHERE submit.region_id = 1 GROUP BY species_id ) dt ON (submit.species_id,submit.length) = (dt.species_id,dt.mlength) WHERE submit.region_id = 1 ORDER BY submit.species_id "; $records_result1 = mysql_query($records1) or die(mysql_error());while($row = mysql_fetch_array($records_result1)) { $length = $row['length']; $species_id = $row['species_id']; $angler = $row['angler']; $image = $row['image']; $yyyy = $row['yyyy']; $dd = $row['dd']; $mm = $row['mm']; //associate names with proper id numbers get_angler_handle($angler); get_species($species_id); Quote Link to comment Share on other sites More sharing options...
Jessica Posted March 2, 2013 Share Posted March 2, 2013 ORDER BY submit.species_id Change that. Quote Link to comment Share on other sites More sharing options...
ozolinse Posted March 2, 2013 Author Share Posted March 2, 2013 That was the first thing I tried before posting... I changed that to ORDER BY submit.species_name and also tried ORDER BY species_name and with both different changes I get an error that pops up on the page like "Unknown column 'submit.species_name' in 'order clause'' Quote Link to comment Share on other sites More sharing options...
Solution kicken Posted March 2, 2013 Solution Share Posted March 2, 2013 You need to join to the species table in order to gain access to the name column. SELECT angler ,team_id ,dt.species_id ,length ,image ,yyyy ,mm ,dd FROM submit join (SELECT species_id, max(length) as mlength FROM submit WHERE submit.region_id = 1 GROUP BY species_id ) dt ON (submit.species_id,submit.length) = (dt.species_id,dt.mlength) INNER JOIN species ON species.species_id=submit.species_id WHERE submit.region_id = 1 ORDER BY species.species_name Quote Link to comment Share on other sites More sharing options...
mikosiko Posted March 2, 2013 Share Posted March 2, 2013 Kichen's answer is pointing you in the right direction, with that most likely your $ query_a seems to dont be needed; also will be interesting to see what the 2 last functions get_angler_handle() and get_species () are used for..if those are only getting the angler name and the specie name then they could be not needed with kichen's solution... same as the variable $speciesname what it is used for? Quote Link to comment Share on other sites More sharing options...
Jessica Posted March 2, 2013 Share Posted March 2, 2013 That's what I get for reading so late at night. Quote Link to comment Share on other sites More sharing options...
ozolinse Posted March 2, 2013 Author Share Posted March 2, 2013 Thanks Kicken... you were spot on! Thanks for the help regarding the join command! Quote Link to comment Share on other sites More sharing options...
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