Simple Image Swap?

[xProteuSx]

I have two files on a server, and I want to swap filenames like this:

 

image1.jpg -> image2.jpg

image2.jpg -> image1.jpg

 

I cannot get this to work.  Obviously I cannot do it this way because then I would end up with two copies of the same file, so I have tried this:

 

 

$file1 = "image1.jpg";
$file2 = "image2.jpg";
$temp1 = "temp1.jpg";
$temp2 = "temp2.jpg";

rename($file1, $temp1);
rename($file2, $temp2);
rename($temp1, $file2);
rename($temp2, $file1);
 

 

 

 

Also, I have tried this:

 

 

$file1 = "image1.jpg";
$file2 = "image2.jpg";
$temp1 = "temp1.jpg";
$temp2 = "temp2.jpg";

copy($file1, $temp1);
copy($file2, $temp2);
unlink($file1);
unlink($file2);
rename($temp1, $file2)
rename($temp2, $file1);
 

 

I have spent about 3 hours on this seemingly simple code     Please have mercy on me!  

[Jessica]

Rename($file1, 'temp');

Rename($file2, 'file1);

Rename($file1, 'file2');

 

Pseudo code.

[xProteuSx]

I think you meant:

 

Rename($file1, 'temp');
Rename($file2, '$file1);
Rename($temp , '$file1');

 

... its been tried

[xProteuSx]

oops ...

 

Rename($file1, 'temp');
Rename($file2, '$file1);
Rename($temp , '$file2');

[xProteuSx]

Doesn't work for some reason.

[Jessica]

Post your actual code.

[xProteuSx]

Variables:

 

$img_thumb1 = $nfilename1 = "Venezuela_p79_1000_Bolivares_1998_t.jpg";

$img_thumb2 = $nfilename2 = "Venezuela_p82_20000_Bolivares_1998_t.jpg";

 

$temp1 = "../upload/283/temp1.jpg";

$temp2 = "../upload/283/temp2.jpg";

$file1 = "../upload/283/" . $img_thumb1;

$file2 = "../upload/283/" . $img_thumb2;

 

Different things that I have tried:

 

rename($file1, $temp1);

rename($file2, $file1);

rename($temp1, $file1);

 

... and ...

 

copy($file1, $temp1);

copy($file2, $temp2);

unlink($file1);

unlink($file2);

rename($temp1, $nfilename2);

rename($temp2, $nfilename1);

 

... and ...

 

rename ($file1, $temp1);

rename ($file2, $temp2);

rename($temp1, $nfilename2);

rename($temp2, $nfilename1);

 

I wonder if this has something to do with 'script speed vs renaming speed' or 'script speed vs copying speed'.

[Jessica]

rename($file1, $temp1);

rename($file2, $file1);

rename($temp1, $file2);

[xProteuSx]

Yeah, sorry, I had this:

 

rename($file1, $temp1);
rename($file2, $file1);
rename($temp1, $file2);

 

(I just gave you some other code).

 

This code only does the first half of the job.  In the end both thumbs end up being the same.

[xProteuSx]

Also tried this:

 

 

copy($file1, $temp1);

copy($file2, $temp2);

copy($temp1, $file2);

copy($temp2, $file1);

unset($temp1);

unset($temp2);

[xProteuSx]

OK, this seems to work (just needed to refresh the browser):

 

 

copy($file1, $temp1);

copy($file2, $temp2);

copy($temp1, $file2);

copy($temp2, $file1);

unset($temp1);

unset($temp2);

[Jessica]

If you want to take twice as many steps, sure.

[xProteuSx]

Seems like all the code was working ... it was just an issue with refreshing page so that it overwrote the cached files.  *sheepish grin*