php warning mesage

[subhomoy]

here is a little bit of code that i've done to check the values against the database values. Every Thing is working fine but i'm getting an warning message. I can't get rid of the warning message. plz help me.

 

The code is shown below

<?php
        echo $ip = $_SERVER['REMOTE_ADDR'];
       echo "<br />";
        echo $date = date("Y-m-d");
         echo "<br />";
     
         $ip1 = mysql_query("SELECT * FROM ip WHERE date='$date' AND ip='$ip'");
        while($row = mysql_fetch_array($ip1)){
            $d = $row['date'];
            $i = $row['ip'];
        }
        if($i == $ip && $d == $date)    <--------------------------------------------------------------------- the warnings....
            echo 'You have already visited the page today.';
        else {
            $insert_ip = mysql_query("INSERT INTO ip (id,date,ip) VALUES('','$date','$ip')") or die(mysql_errno()); 
        echo 'Thank you for your visit';
        }
        ?>

The warnig mesage i'm getting is

 

Notice: Undefined variable: i in C:\xampp\htdocs\Mobitalk\index.php on line 23

Any help will be appreciated..

[runnerjp]

An Undefined index means that you are referencing an array index that doesn't exist yet. Have you checked if $i is set? 

<?php
        echo $ip = $_SERVER['REMOTE_ADDR'];
       echo "<br />";
        echo $date = date("Y-m-d");
         echo "<br />";
$d = "";
            $i = "";
     
         $ip1 = mysql_query("SELECT * FROM ip WHERE date='$date' AND ip='$ip'");
        while($row = mysql_fetch_array($ip1)){
            $d = $row['date'];
            $i = $row['ip'];
        }
        if($i == $ip && $d == $date)    <--------------------------------------------------------------------- the warnings....
            echo 'You have already visited the page today.';
        else {
            $insert_ip = mysql_query("INSERT INTO ip (id,date,ip) VALUES('','$date','$ip')") or die(mysql_errno()); 
        echo 'Thank you for your visit';
        }
        ?>

TRY THE ABOVE