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loop through SQL results to print an HTML table

Go to solution Solved by jasonxxx102,

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Ok, so I have a main page that grabs data from a MySQL db and posts it into a dropdown menu


see here:

$sql = "SELECT * FROM 4000Series";
$result = $con->query($sql);

print "Select your GPU: <select name='gpuId'>";
while ($row = $result->fetch_assoc())
    print "<option value='" .$row["id"] . "'>" . $row["gpu"] . "</option>";
print "</select> </br>\n";

This works fine, from here I'm passing the POST data from the option values to a new page (basically the option values correspond directly to the "id" value in my SQL db).


The values are passed onto the new page fine, but when I try to setup an SQL select statement to grab the row with the corresponding "id" value and print it out with a while loop I'm shooting a blank.


Here's the code for the second page

$id = $_POST['gpuId'];

**Connect to sql db here**

$sql = "SELECT * FROM 4000Series WHERE $id ='id'";
$result = $con->query($sql);

echo "<table>"; 

while ($row = $result->fetch_assoc()){   
echo "<tr><td>" . $row['id'] . "</td><td>" . $row['gpu'] . "</td></tr>";  

echo "</table>";

When I view the source it prints out the table tags but nothing in the while loop, any ideas?

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you have a $ in front of your id column name in your query, you are also missing the $ in front of the $id variable name in your query OR you could remove the single-quotes from around the id column name in your query.


if you include a debugging step where you echo out your sql query statement, you would have likely seen this problem.

Edited by mac_gyver
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