i am a beginner and i really need some help.

[cooks]

hi there i am a beginner in PHP and i really would like some help with this.....

 

i need to make use of the date() function to retrieve the current date. Use the split() function to retrieve the day month and the year from the current date. and the calculations to display the age.

 

if anyone could help me with this it would be amazing.

 

thank you!!

newagecalc.php

[NiallAA]

print(Date("F jS Y")); 

will display:

 

August 29th 2014

 

http://php.net/manual/en/function.date.php

Edited August 29, 2014 by NiallAA

[cyberRobot]

You could format the output from the date() function so it contains some sort of separator. Then just use explode() to break apart the date. More information about both functions can be found in the PHP manual:

• date() - http://php.net/manual/en/function.date.php
• explode() - http://php.net/manual/en/function.explode.php

 

Side note: the split() function has been deprecated.

Edited August 29, 2014 by cyberRobot

[Strider64]

Or you could just do this 

<?php
$born = new DateTime("August 28, 1964");
$now = new DateTime();
echo $now->format("F j, Y");  // Output August 29, 2014 format:
echo '<br>';
$age = $born->diff($now);
echo "I am " . $age->y . " years old<br>";

More info on DateTime() here: http://php.net/manual/en/class.datetime.php

[mac_gyver]

^^^ except that the stated age of something depends on if the birthday has or has not occurred yet in the current year. the age is the difference in years, subtract one if the month and day are less than the current month and day.

[Strider64]

Maybe something like? 

$calendarDay = new DateTime( $month . ' ' . $day . ', ' . $year );
$age = $born->diff($calendarDay);

I just wrote first post on how easy it is to do it this way and the learning part is actually figuring it out on your own (in my opinion).