wyy Posted November 9, 2014 Share Posted November 9, 2014 I'm trying to use checkbox to choose multiple data and submit(button 'Send SMS') them and direct them to another page, which will send text SMS to the numbers chosen. But when I try to click on one checkbox, it automatically directs me to the next page, without having to click on the 'Send SMS' button. I tried to see which part is the problem, but I can't determine which one is wrong. Please help! Thank you. <script type="text/javascript"> function checkedAll (frm1) {var aa= document.getElementById('frm1'); if (checked == false) { checked = true } else { checked = false }for (var i =0; i < aa.elements.length; i++){ aa.elements[i].checked = checked;} } </script> <TABLE width="1106" border="1" align="center" cellpadding="5" cellspacing="2" > <tr> <td colspan="9"> <form id ="frm1" action="sms_latecomers.php"> <input type='checkbox' name='checkall' onclick='checkedAll(frm1);' value=""> <input type="submit" name="Submit" id="button" value="SMS Reminder" style="background:#FFCC33"/> </td> </tr> <TR bgcolor="#996699"> <?php $count=0; ?> <TH width="32"></TH> <TH width="37"> <span class="style1"> <div align="center">No. </div></span></TH> <th width="101"><span class="style1">SUPERVISOR ID</span></th> <th width="101"><span class="style1">EMPLOYEE ID</span></th> <th width="153"><span class="style1">EMPLOYEE NAME</span></th> <th width="124"><span class="style1">DATE</span></th> <th width="153"><span class="style1">LATE CHECK IN</span></th> </TR> <?php while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { ?> <TR> <TD><input type="checkbox" name="chk1" value="<?php echo $row['supervisor_telno']; ?>" onClick="window.open('sms_latecomers.php?employee_id=<?php echo $row['employee_id']; ?>&supervisor_telno=<?php echo $row['supervisor_telno']; ?>');"></TD> <TD height="66">[bad html removed]<input type="checkbox" name="chk1" >--> <?php $count=$count+1; print($count);?></TD> <TD><div align="center"><?php echo $row['supervisor_id']; ?></div></TD> <TD><div align="center"><?php echo $row['employee_id']; ?></div></TD> <TD><div align="center"><?php echo $row['employee_name']; ?></div></TD> <TD><div align="center"><?php echo $row['DATE']; ?></div></TD> <TD><div align="center"><?php echo $row['TIME']; ?></div></TD> </TR> <?php } ?>[bad html removed]</form>--> </TABLE> Quote Link to comment https://forums.phpfreaks.com/topic/292377-checkbox-button-not-working-properly/ Share on other sites More sharing options...
ginerjm Posted November 9, 2014 Share Posted November 9, 2014 Way too many errors in this code to even try to understand. Why do you even attempt to pass that frm1 thing as a constant to the js function when in the js you don't even try to use the supposed-passed-in argument? Why do you use a td to encase both a span and a div just to apply styles when you could just do it to the td tag itself? so much work to do...... One suggestion - work on separating your html from your logic. One is just that logic - the other is presentation. Don't mix the two except where necessary. Quote Link to comment https://forums.phpfreaks.com/topic/292377-checkbox-button-not-working-properly/#findComment-1496175 Share on other sites More sharing options...
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