This is interested. Haven't noticed until now. Ajax won't show row the first time.

[helloworld001]

So I have a simple script that adds and returns mysql data without refreshing the page.  Everything works as it should.  The only issue that I've noticed is that if I login as a user and insert a record(text) the FIRST time, it won't return that record in the row below. Not until I refresh the page.  Now if I delete that record and insert a new record, it will then automatically return the record without the page refresh, as it should.

 

Can you tell me why this is happening?

 

Here is my js code.

<script>
	$(document).ready(function(){
	
		var recordId	=	$("#record-id").val();
		
		function showRecord(){
			$.ajax({
				type: "POST",
				url:  "bid-actions.php",
				data: "recordId="+recordId+"&action=showRecord",
				success:function(data){
					$(".show-records").html(data);
				}
		  });
		}

		showRecord();

		$(document).on('click','#record-submit',function() {
			
			var message		=	$("#message").val();
			var recordId	=	$("#record-id").val();
			
			$.ajax({
				type: "POST",
				url:  "bid-actions.php",
				data: "message="+message+"&recordId="+recordId+"&action=insertRecord",
				success:function(data){
					
					showRecord();
					$("#message").val('');
					
				}

			});
			
		});
   });
</script>

  Html code.

<div id="record-submit-form">
	<input type="hidden" id="record-id"  value="<?php echo $record_id; ?>">
	<textarea id="message"></textarea>
	<input type="button" id="record-submit" value="Submit">
</div>

<div class="show-records">
</div>

Edited March 17, 2015 by helloworld001

[Psycho]

Can't really tell with what you've provided. But, I notice that the showRecord() function works by checking the value of the field "record-id". If you create a new record, then the ID of that record would need to be populated into that field in order to run the showRecord() function on it. I'm guessing that has something to do with the problem.

[helloworld001]

Can't really tell with what you've provided. But, I notice that the showRecord() function works by checking the value of the field "record-id". If you create a new record, then the ID of that record would need to be populated into that field in order to run the showRecord() function on it. I'm guessing that has something to do with the problem.

 

Well the forum is back online. 

 

The problem is fixed now.  My code is correct.  It's just that I was hiding the output using php if statement.