phpstreak Posted April 14, 2015 Share Posted April 14, 2015 (edited) Hello everyone! I would like to need some help from someone who understands the basics of PHP. About the problem: I am supposed to make the user's input number multiple (a number between 0 and 10) with the text string the user has written. For example, the user writes "Hello" and "5", "Hello" should be printed out five times. I must use a for-loop and a while-loop to solve it.) Maybe it has to do with something called parameter. Would be thankful for some help! This is my current code: <form method="POST"> Message: <input type="text" name="message"/> Number: <input type="text" name="number"/> <input type="submit" value="OK!" name="submit" /> </form> <?php if(isset( $_POST["submit"] ) ) { $message = $_POST["message"]; $number = $_POST["number"]; ?> <?php for ($random = 0; $random < 10; $random = $random + $number) { echo "<ul><li>$message</li></ul>"; } ?> <?php } ?> Edited April 14, 2015 by phpstreak Quote Link to comment Share on other sites More sharing options...
requinix Posted April 14, 2015 Share Posted April 14, 2015 (edited) You need a for loop and a while loop? One for loop is plenty for this. You can do a for loop or a while loop, though... [edit] Anyways, with just a for loop, you're close. for (first statement; condition to keep executing; statement to execute at the end of the loop's body) {What you have: start with $random=0, keep executing as long as $random is less than 10, and every time at the end of the loop's body (that is, after the echo) it will increment $random by $number. What that should be: start with $random=0 (although a better variable name would be nice), keep executing as long as $random is less than $number, and every time it increments $random by one. Edited April 14, 2015 by requinix Quote Link to comment Share on other sites More sharing options...
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