what is wrong with the code?

azra · April 19, 2015



                 1. HTML FORM


              #for user to enter the data


             <html>

                <title>reg</title>

                <style type="text/css">

                			body {

                				background-color: rgb(200,200,200);

                				color: white;

                				padding: 20px;

                				font-family: Arial, Verdana, sans-serif;}

                			h4 {

                				background-color: DarkCyan;

                				padding: inherit;}

                			h3 {

                				background-color: #ee3e80;

                				padding: inherit;}

                			p {

                				background-color: white;

                				color: rgb(100,100,90);

                				padding: inherit;}

                </style>


                <form method="POST" action="login_back.php" enctype="multipart/form-data"></br>

                &nbsp<font color="DarkCyan"> Choose a user name:</font> <input type="text" name="username">

                </br></br>

                &nbsp<font color="DarkCyan"> First name:</font> <input type="text" name="firstname"/>

                </br></br>

                &nbsp<font color="DarkCyan">  Last name:</font><input type="text" name="lastname"/>

                </br></br>

                &nbsp<font color="DarkCyan"> File: <input type="file" name="image"></font>

                </br></br>

                <input type="submit" value="Save and Proceed">

                </form>

                </html>



                ----------

                 2 STORING IN DATABASE

            #backend processing to store and retrieve data from db 


                <?php

                #echo "<body style='background-color:rgb(200,200,200)'>";

                session_start();

                if( isset($_POST['username']) && isset($_FILES['image']) )

                {

                $_SESSION['username']=$_POST['username'];

                $_SESSION['firstname']=$_POST['firstname'];

                $lastname=$_POST['lastname'];

                $file=$_FILES['image']['tmp_name'];

                $image_size=getimagesize($_FILES['image']['tmp_name']);

                if(!isset($file))

                	echo"please select an image";

                else

                {

                $image_name=$_FILES['image']['name']; //grabing image name

                $image_size=getimagesize($_FILES['image']['tmp_name']); //getting image size

                }

                echo "</br>";



                #connection to db

                mysql_connect("localhost","root","")or die(mysql_error());

                mysql_select_db("wordgraphic")or die(mysql_error());




                #checking the available username

                $query = mysql_query("SELECT * FROM userdata WHERE username = '" . $_SESSION['username'] . "'" ); 

                $ans=mysql_num_rows($query);

                if ($ans > 0) 

                { 

                     echo "Username already in use please try another.";


                }


                else if($image_size==FALSE)

                {

                echo"That's not an image.";


                }


                else

                {

                #Insert data into mysql


                #1.Inserting user name & image into db

                $sql="INSERT INTO userdata(username, firstname, lastname, image)VALUES('" . $_SESSION['username'] . "', '" . $_SESSION['firstname'] . "', '$lastname','$image')";

                $result1=mysql_query($sql);


                if($result1)

                {

                echo "</br>";

                echo "Registration successful";

                echo "</br>";


                //displaying image

                $lastid=mysql_insert_id();//get the id of the last record

                echo "uploaded image is :";

                echo "<img src='get.php?id=".$lastid."'>";   >  this command has some mistake


                }#if insertion into db successful

                else 

                {

                echo "Problem in database operation";

                }

                }# else block of unique username n img

                }#end of isset

                ?>



            ----------


                3. GET.PHP

           #additional file that retrieve image from database


                <?php

                #connection to db

                mysql_connect("localhost","root","")or die(mysql_error());

                mysql_select_db("wordgraphic")or die(mysql_error());

                if(isset($_REQUEST['id']) ) > this block of code is not runninng

                {

                $mid=(int)($_REQUEST['id']);


                $image=mysql_query("SELECT * FROM userdata WHERE id=$mid") or die("Invalid query: " . mysql_error());

                $image=mysql_fetch_assoc($image);

                $image=$image['image'];

                header("Content-type: image/jpeg");

                echo $image;

                }

                else

                    {

              	echo"error";

                     }

      ?>

ginerjm · April 19, 2015

You should really elaborate on what you need help with. What exactly isn't right in your mind?

ginerjm · April 19, 2015

Having now seen your duplicate posting (!!!) I will offer this..

1 - as was already mentioned, turn on error checking. (See my signature)

2 - Where you try to insert a record you reference the $image var. That has not been defined. And what exactly are you trying to store in your db - an image file name? Did you ever save the uploaded file someplace? I don't see any code for that. And since you never assigned a value to $image, you're probably getting an error but not seeing it displayed.

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what is wrong with the code?

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