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Almost.

 

There is a class somewhere named "Table" in the "Cake\ORM" namespace. Odds are it will be in a file Cake\ORM\Table.php (or .class.php or whatever) but that is not always true.

 

Normally to refer to that class in code you would have to write the full path, like

$table = new \Cake\ORM\Table();
With a use you can tell PHP that any mention of "Table" actually refers to Cake\ORM\Table, so you can write the shorter

$table = new Table();
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Almost.

 

There is a class somewhere named "Table" in the "Cake\ORM" namespace. Odds are it will be in a file Cake\ORM\Table.php (or .class.php or whatever) but that is not always true.

 

Normally to refer to that class in code you would have to write the full path, like

$table = new \Cake\ORM\Table();
With a use you can tell PHP that any mention of "Table" actually refers to Cake\ORM\Table, so you can write the shorter

$table = new Table();

arent Cake and ORM folders?

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They may be folders, but in this case you're dealing with namespaces, not folder structure. Assuming everything in Cake is using an autoloader, I would expect to find the namespaces correspond with the directory structure, but it certainly doesn't have to.

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Almost.

 

There is a class somewhere named "Table" in the "Cake\ORM" namespace. Odds are it will be in a file Cake\ORM\Table.php (or .class.php or whatever) but that is not always true.

 

Normally to refer to that class in code you would have to write the full path, like

$table = new \Cake\ORM\Table();
With a use you can tell PHP that any mention of "Table" actually refers to Cake\ORM\Table, so you can write the shorter

$table = new Table();

 

arent Cake and ORM folders?

 

They may be folders in this case, but namespaces do not have to have a matching directory structure.

 

In order to follow the PSR-0 standard, namespaces do have to have a matching directory structure. I'm not sure if CakePHP follows PSR-0 or not.

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