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Need help getting mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given error.


Go to solution Solved by benanamen,

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<?php
//get values from form in login page
$username=$_POST['user'];
$password=$_POST['pass'];

//connect to the server and select the database
$dbserver="localhost";
$dbusername="root";
$dbpassword="";
$dbname="";

$conn=mysqli_connect($dbserver,$dbusername,$dbpassword,$dbname)or die("Connection to Database Server Failed");

//to prevent mysql injection
$username=stripcslashes($username);
$password=stripcslashes($password);
$username=mysqli_real_escape_string($conn, $username);
$password=mysqli_real_escape_string($conn, $password);


//query the database for user
$sql="select * from student where username='$username' and password='$password'";
$result= mysqli_query($conn, $sql);
$row=mysqli_fetch_array($result);
if($row['username']==$username && $row['password']==$password){
echo "Login Successfull.. Welcome".$row['username'];
}
else{
echo "Failed to login";
}

?>

 

  • Solution

Problem is not solved. Where are you people constantly coming up with this same bad code over and over again? Pretty much everything you could do wrong here, you did.

 

Save yourself troubles and start using PDO. It's how we code in 2017. https://phpdelusions.net/pdo

You can now close this thread.

 

We don't do that, because sometimes there are additional comments from other users. But you can mark the topic as solved by choosing the best answer and then clicking the “Best Answer” button.

  • Like 1
This thread is more than a year old. Please don't revive it unless you have something important to add.

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