multisort; flags (defines) v/s variables

[fatkatie]

This works fine if $field_one_order is replaced with SORT_ASC.

   array_multisort($field_one, $field_one_order, $field_two, SORT_ASC, $data_array);

It gives the following error if a variable is used in place of a define
 

 

array_multisort(): Argument #2 is expected to be an array or a sort flag

 

 

I dump the var and it is indeed valued as expected.

 

$field_one_order = 'SORT_ASC'

 

Is the use of a variable not allowed here?   If a def is required, can a variable be typed as one?

[requinix]

'SORT_ASC' is a string. SORT_ASC is a constant.

[mac_gyver]

the php defined constants are integer values. if you put the actual value into a variable, this will work. you have a string now, the name of the defined constant, not its value.

 

Use - 

$field_one_order = SORT_ASC;

You probably have this now - 

$field_one_order = 'SORT_ASC';

[fatkatie]

   $x = constant($field_one_order); (or plain assignment of def value)

 

Should have known that.

 

Thanks.

Edited March 18, 2018 by fatkatie

[requinix]

There's really no reason to use constant() or a string here. Just do the regular assignment like mac_gyver said.