Help with in_array() and chr()

[thepip3r]

I have an array $chars that has some of the 256 characters but not all in it (ie abc,ABC,123,!@#, and some of the upper ASCII characters as well) when I try to do an evaluation using in_array(), it always evaluates to true and I can't seem to figure out why; can anyone offer any pointers?

[code]
echo "<table width=\"100%\"><tr>";

for ($i=1; $i<256; $i++) {
if (in_array(chr($i), $chars)) {
if ($i % 10 == 0) {
echo "<td>1 $i: <b>" . chr($i) . "</b><br /></td></tr><tr>";
} else {
echo "<td>1 $i: <b>" . chr($i) . "</b><br /></td>";
}
} else {
if ($i % 10 == 0) {
echo "<td>2 $i: " . chr($i) . "<br /></td></tr><tr>";
} else {
echo "<td>2 $i: " . chr($i) . "<br /></td>";
}
}
}

echo "</tr></table>";[/code]

[hitman6003]

Both of your sub-if statements are the same:

[code]if ($i % 10 == 0) {
echo "<td>1 $i: <b>" . chr($i) . "</b><br /></td></tr><tr>";[/code]

[code]if ($i % 10 == 0) {
echo "<td>2 $i: " . chr($i) . "<br /></td></tr><tr>";[/code]

[thepip3r]

no they're not.  the second sub-if entries are prefaced with a number 2 and also, the chr($i) is not encapsulated in bold tags -- those two indicators are how I know that it's always evaluating to true.

[kenrbnsn]

Can you show us a dump of the array $chars? It is unclear exactly what you are trying to do.

Ken

[thepip3r]

what don't you understand??  my array chars looks something like:

[code]
$chars[] = "a";
$chars[] = "b";
$chars[] = "A";
$chars[] = "B";
$chars[] = "!";
$chars[] = "@";
$chars[] = chr(192);
$chars[] = chr(215);

echo "<table width=\"100%\"><tr>";

for ($i=1; $i<256; $i++) {
if (in_array(chr($i), $chars)) {
if ($i % 10 == 0) {
echo "<td>1 $i: <b>" . chr($i) . "</b><br /></td></tr><tr>";
} else {
echo "<td>1 $i: <b>" . chr($i) . "</b><br /></td>";
}
} else {
if ($i % 10 == 0) {
echo "<td>2 $i: " . chr($i) . "<br /></td></tr><tr>";
} else {
echo "<td>2 $i: " . chr($i) . "<br /></td>";
}
}
}

echo "</tr></table>";[/code]

..so I'm looping thorugh 255 out of the 256 chars possible (1-255 (excluding 0 which is null))  to see if they exist in my array.  If they do, it's supposed to enbolden those chars.  If it doesn't, it supposed to format them normally.  Hence the bold tags in the first set of sub-ifs and the non-inclusion of the bold tags in the second sub-if.

[Azu]

Maybe use something like[code]$chars[0] = "a";
$chars[1] = "b";
$chars[2] = "A";
$chars[3] = "B";
$chars[4] = "!";
$chars[5] = "@";
$chars[6] = chr(192);
$chars[7] = chr(215);[/code]instead?