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I'm having problem with this code. It's supposed to pull a  link from a database and feed it into an iframe src to make the video display on screen.

I'm getting a white box...

It seems like the "address" variable is getting dropped or something, out of scope?

here is the code:

 

<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */

$link = mysqli_connect("localhost", "root", "Mm62Tic8FH", "music");

$rand_num;
$rowcount;

// Check connection
if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Attempt select query execution
$sql = "SELECT * FROM songs";


if($result = mysqli_query($link, $sql)){ // query results stored in "result"
    if(mysqli_num_rows($result) > 0){
        $rowcount = mysqli_num_rows($result);
        $rand_num = rand(0,$rowcount - 1);
        $address = "5";
        echo "<table>";
            
        while($row = mysqli_fetch_array($result)){
            echo "<tr>";
                echo "<td>" . $row['artist_name'] . "</td>";
                echo "<td>" . $row['song_name'] . "</td>";
                echo "<td>" . $row['url'] . "</td>";
                echo "<td>" . $row['item_id'] . "</td>";
                echo "<td>" . $rand_num;

            echo "</tr>"; 

            if ($rand_num == $row['item_id']) {
                $address = "https://www.youtube.com/embed/". $row['url'];
            }

            echo "----".$address."----";

        }
        echo "</table>";
        // Free result set
        mysqli_free_result($result);
    } else{
        echo "No records matching your query were found.";
    }
} else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
 
// Close connection
mysqli_close($link);

?>

   
<iframe width="420" height="315"
    src=<?php  $address ?>>
</iframe> 

 

Link to comment
https://forums.phpfreaks.com/topic/311652-inserting-variable-into-iframe/
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