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Problem sending formdata to php using fetch


eaglehopes
Go to solution Solved by Strider64,

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Hi all. Today I tried a form which sends data inside the formData object to a php file with fetch method. But when I try to capture the sended "thumbing" variable from php file, I could not got it! 

sql.html 

<form id="thumbEvaluationForm" method="POST" action="sql_connection.php" >  
  <div>
    <input id="thumbup" type="radio" name="thumbing" value="1" >
    <input id="thumbdown" type="radio" name="thumbing" value="-1" >
    <input type="submit" name="Submit" > 
  </div>
</form>

and sql_connection.php file content : 

<?php
	error_reporting(E_ALL);
	mysqli_report(MYSQLI_REPORT_OFF);
	unset($thumbing);
		
	if( isset($_REQUEST["thumbing"] ) ) { 
		echo " request get as thumbing ".$_REQUEST["thumbing"];
	}

	if( isset($_POST["thumbing"] ) ) {
		$thumbing=$_POST["thumbing"];
		echo "thumbing is set : ".$thumbing;
	} else {
		echo "thumbing is not set...";
	}

then I add a listener to submit event of the form to send formdata to php file(sql_connection.php). 

window.onload= function() { 
	var thumbform = document.getElementById("thumbEvaluationForm");

	thumbform.addEventListener('submit', (event) => {
		event.preventDefault(); // disable event's default behaviour
		const thumbFormData = new FormData(thumbform); 
		alert("thumbing is send as : " + thumbFormData.get("thumbing")); // got correct result of thumbing from radio button ! 
		fetch("sql_connection.php", {
			method: 'POST',
			body: thumbFormData
		})
		.then(response => {
			if (response.ok) {
			// Handle the successful response
			} else {
			// Handle the error
			}
		})
		.catch(error => {
		// Handle the error
		});
	});
}

I could not get $_POST['thumbing'] or $_REQUEST['thumbing'] in sql_connection.php code? Why? Where is the mistake? Thanks.

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  • Solution

You need to do something like this ->

        // Add an event listener to the edit form's submit event
        editForm.addEventListener("submit", async function (event) {
            // Prevent the default form submit behavior
            event.preventDefault();

            // Create a FormData object from the edit form
            const formData = new FormData(editForm);
            //console.log("form data", formData);
            // Send a POST request to the edit_update_blog.php endpoint with the form data
            const response = await fetch("edit_update_blog.php", {
                method: "POST",
                body: formData,
            });

            // Check if the request was successful
            if (response.ok) {
                const result = await response.json();
                console.log(result);
                // If the response has a "success" property and its value is true, clear the form
                if (result.success) {
                    resultInput.value = '';          // Clear the current value of the search input field
                    resultInput.placeholder = "New Search"; // Set the placeholder to `New Search`
                    image_for_edit_record.src = "";
                    image_for_edit_record.alt = "";
                    editForm.reset(); // Resetting the edit form
                    searchForm.reset(); // Resetting the search form

                    // Reset select box to default (first) option
                    const selectBox = document.querySelector('select[name="heading"]');
                    selectBox.selectedIndex = 0;
                }

            } else {
                console.error(
                    "Error submitting the form:",
                    response.status,
                    response.statusText
                );
                // Handle error response
            }
        });

also using `console.log` helps in debugging, plus your `sql_connection.php` is expecting back json data back.

Edited by Strider64
  • Great Answer 1
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1 hour ago, kicken said:

Your code doesn't show you doing anything with the response, so how do you know you're not receiving the data in your script?

I think I do something with these? 

if( isset($_POST["thumbing"] ) ) {
		$thumbing=$_POST["thumbing"];
		echo "thumbing is set : ".$thumbing;
	} else {
		echo "thumbing is not set...";
	}

I think I echoed if the "thumbing" variable passed successfully? Didn't I do it correctly?

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Thanks all, I corrected my code and finally got and see correct returns for "thumbing" variable and use it in my php code to add it to mysql database.

I did not changed anything in my fetch code(so I did not re-post it here), but I did : 

1. I used $_REQUEST[] to see whether my response goes there or not, but finally I deleted $_REQUEST[] line.

2. I used strider64's code to see all errors in console. As Barand's suggestion(after strider64's code), I looked to the console and all errors shown in console in fantastically detailed such that finding and correcting my code takes about a minute ! Thanks strider64! Then I returned to my own code and it worked like a charm!

3.  replace wrong string concetanation operator (+) in my php code(sql_connection.php) with correct ones (.) Yes, Chrome's F12-console is very helpful in debugging ! 

I added my php code to use thumbing result to add it into my mariadb database (in sql_connection.php). I gave it, maybe, I hope it helps someone :D . My code was :

 

if( isset($thumbing) ) {
  echo "thumbing is ok" . $thumbing;
  addThumbValues($sendedFilePath,$thumbing);
}
	
function addThumbValues($thumbResponse)  {
		$up=""; 
		$down="";
		// TODO can use ternary operator to save code lines in future
		if($thumbResponse == 1 ) {
			$up=1;
			$down="0";
		} else if (thumbResponse == -1) {
			$down=1;
			$up="0";
		}
		
		$conn = OpenConnection(); // open database connection
		
		$sql = mysqli_prepare($conn,"INSERT INTO `thumbs` (up,down) VALUES ('$up','$down')"); 
		if($sql !== FALSE){
			if(mysqli_stmt_execute($sql)){
				//echo "New record created successfully";
			} else {
				echo mysqli_stmt_error($sql);
				echo "Error in record creation : failed!";
			}
		} else{
			echo mysqli_error($conn) ." sql statement is false";	
		}
		CloseConnection($conn); // close database connection
	}

Thanks. 

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Sorry, I had made a mistake, I noticed it ! I corrected my code as above  :

On 9/3/2023 at 12:34 AM, eaglehopes said:
// TODO can use ternary operator to save code lines in future
		if($thumbResponse == 1 ) {
			$up=1;
			$down="0";
		} else if ($thumbResponse == -1) {  // I had forgotten to add $ sign before variable
			$down=1;
			$up="0";
		}

 

:D

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