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[SOLVED] please help - Unable to get value in &_POST for a array variable

am_25

By am_25
in PHP Coding Help

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am_25 Newbie

am_25

Posted
Posted

Hi,

I'm passing a array varible thru a multi select list box, but unable to get any value from it thru the $_POST, it returns no value at all. Please see the following code.

 

No value is returned for $test=$_POST['test'];

 

<?php
include "connect.php";
echo '<pre>' . print_r($_POST,true) . '</pre>';
if (isset($_POST['submit']))
{	
$test=$_POST['test'];
$n=count($test);
echo "You selected ".$test." value. <br />";

if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
}
?>
<html>
<body>
<form action="multiple.php" method="post">
<?php
$sql2="SELECT distinct(designation) from empdet order by designation asc ";
$result2=mysql_query($sql2);
?>
<SELECT multiple ="multiple" name="test[]">
<?php

While ($row=mysql_fetch_assoc($result2))
{
$desi=$row['designation'];
  echo "<OPTION  value='$desi'>$desi</OPTION> ";

} ?></select>
&nbsp
<input type='submit' name='submit' value='submit'></form>
</form></td></tr>
</body>
</html>

am_25 Newbie

am_25

Posted
  • Author
Posted

Nope it does not work. If the value is Manager, it just returns M.

The select name is just test, I didnot name it as an array. If I place a [] with test, then nothing gets stored in the variable.

 

 

<?php

include "connect.php";

echo '<pre>' . print_r($_POST,true) . '</pre>';

 

if (isset($_POST['submit']))

{

$test=$_POST['test'];

//$n=count($test);

 

for($i=0;$i<sizeof($_POST["test"]);$i++)

{

echo "You selected ".$_POST["test"][$i]."<br />";

}

//echo "You selected ".$test." value. <br />";

 

if ($test){

foreach ($test as $t){echo 'You selected ',$t,'<br />';}

}

}

?>

<html>

<body>

<form action="multiple.php" method="post">

<?php

$sql2="SELECT distinct(designation) from empdet order by designation asc ";

$result2=mysql_query($sql2);

 

?>

 

<SELECT multiple ="multiple" name="test[]">

<?php

$i=1;

While ($row=mysql_fetch_assoc($result2))

{

$desi=$row['designation'];

 echo "<OPTION  value='$desi'>$desi</OPTION> ";

$i=$i+1;

} ?></select>

&nbsp

<input type='submit' name='submit' value='submit'></form>

</form></td></tr>

</body>

</html>

 

 

 

 

am_25 Newbie

am_25

Posted
  • Author
Posted

Thanks I tried the Online tools example, but it does not work when I retrieve data from the DB.

When the OPTION VALUES are given it works, but when it is retrieved from the DB, the array does not pass any value.

It is very weird

thepip3r Member

thepip3r

Posted
Posted

ok then.. try this because this doesn't make sense.  I've gone over your code but can't seem to find a problem so here's what i want you to do.  Load the page so that your db query runs and builds your select box.  Then view source on that page and post the results here.  i want to see how the raw HTML output looks.

am_25 Newbie

am_25

Posted
  • Author
Posted

Thanks a lot Here is the raw HTML code

 

 

<pre>Array

(

    [test] =>

    [submit] => submit

)

</pre>You selected  value. <br /><html>

<body>

<form action="multiple.php" method="post">

<SELECT multiple ="multiple" name="test[]">

 

<OPTION  value='Manger'>Manger</OPTION> <OPTION  value='Mgr'>Mgr</OPTION> <OPTION  value='QA'>QA</OPTION> <OPTION  value='SE'>SE</OPTION> <OPTION  value='SSE'>SSE</OPTION> </select>

&nbsp

<input type='submit' name='submit' value='submit'></form>

</form></td></tr>

</body>

</html>

kenrbnsn Regular Member

kenrbnsn

Posted
Posted

You have an extraneous "</form></td></tr>" at the end of your source, but that shouldn't make a difference.

 

I took your code and ran it on my server and it works fine.  What version of PHP, type of webserver, and browser are you using?

 

Ken

13th_Star Newbie

13th_Star

Posted
Posted

instead of if ($text) { foreach    try   if ($test == !"") { foreach

That doesn't make sense. If test is going to be an array, check the count();

if(count($test)){

}

 

well everytime I try to use if($blabla)  it does fuck all lol

am_25 Newbie

am_25

Posted
  • Author
Posted

This works

 

<?php
echo '<pre>' . print_r($_POST,true) . '</pre>';

$test=$_POST['test'];
if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
?>
<html>
</body>
<form action="test.php" method="post">

<select name="test[]" multiple="multiple">
<option value="one">one</option>
<option value="two">two</option> 
<option value="three">three</option>
<option value="four">four</option> 
<option value="five">five</option>
</select> 
&nbsp
<input type='submit' name='submit' value='submit'>
</form>
</body>
</html>

 

This does not work, what can the error be, except that the values are from the DB. It is not passed in the array varible. But for a variable it works.

 

<?php
include "connect.php";
echo '<pre>' . print_r($_POST,true) . '</pre>';
if (isset($_POST['submit']))
{	
$test=$_POST['test'];
$n=count($test);
if (count($test)){
   echo " you are inside the loop";
}
echo "You selected ".$test." value. <br />";
if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
}
?>
<html>
<body>
<form action="multiple.php" method="post">
<?php
$sql2="SELECT distinct(designation) from empdet order by designation asc ";
$result2=mysql_query($sql2);?>
<SELECT name="test[]" multiple ="multiple">
<?php
While ($row=mysql_fetch_assoc($result2))
{
//$desi=$row['designation'];
echo "<OPTION  value=\"{$row['designation']}\">{$row['designation']}</OPTION>\n";
} ?></select>
<input type='submit' name='submit' value='submit'>
</form>
</body>
</html>

am_25 Newbie

am_25

Posted
  • Author
Posted

It worked, the problem was very simple.

 

the

include "connect.php"; - line was the problem.

 

Since this line was the first line, all the POST variables were getting lost.

 

I removed this line of code and placed it just before where the SQL was called and viola everything worked.

Thanks for all the help.

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