[SOLVED] please help - Unable to get value in &_POST for a array variable

am_25 · February 12, 2007

Hi,

I'm passing a array varible thru a multi select list box, but unable to get any value from it thru the $_POST, it returns no value at all. Please see the following code.

No value is returned for $test=$_POST['test'];

<?php
include "connect.php";
echo '<pre>' . print_r($_POST,true) . '</pre>';
if (isset($_POST['submit']))
{	
$test=$_POST['test'];
$n=count($test);
echo "You selected ".$test." value. <br />";

if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
}
?>
<html>
<body>
<form action="multiple.php" method="post">
<?php
$sql2="SELECT distinct(designation) from empdet order by designation asc ";
$result2=mysql_query($sql2);
?>
<SELECT multiple ="multiple" name="test[]">
<?php

While ($row=mysql_fetch_assoc($result2))
{
$desi=$row['designation'];
  echo "<OPTION  value='$desi'>$desi</OPTION> ";

} ?></select>
&nbsp
<input type='submit' name='submit' value='submit'></form>
</form></td></tr>
</body>
</html>

paul2463 · February 12, 2007

try removing the [] from around the name of your SELECT multiple

am_25 · February 12, 2007

it works but the problem is, if I select 3 values in the list box, only the last value is stored

for e.g, if I have chosed, MGR, QA,SE - only SE value is displayed.

I want all the values.

paul2463 · February 12, 2007

try this

<?php
if (isset($_POST['submit']))
{	
$test=$_POST['test'];
for($i=0;$i<sizeof($_POST["test"]);$i++) 
{
echo "You selected ".$_POST["test"][$i]."<br />";	
}
}
?>

thepip3r · February 12, 2007

http://onlinetools.org/tricks/using_multiple_select.php

am_25 · February 12, 2007

Nope it does not work. If the value is Manager, it just returns M.

The select name is just test, I didnot name it as an array. If I place a [] with test, then nothing gets stored in the variable.

<?php

include "connect.php";

echo '<pre>' . print_r($_POST,true) . '</pre>';

if (isset($_POST['submit']))

{

$test=$_POST['test'];

//$n=count($test);

for($i=0;$i<sizeof($_POST["test"]);$i++)

{

echo "You selected ".$_POST["test"][$i]."<br />";

}

//echo "You selected ".$test." value. <br />";

if ($test){

foreach ($test as $t){echo 'You selected ',$t,'<br />';}

}

?>

<html>

<body>

<?php

$sql2="SELECT distinct(designation) from empdet order by designation asc ";

$result2=mysql_query($sql2);

?>

<?php

$i=1;

While ($row=mysql_fetch_assoc($result2))

{

$desi=$row['designation'];

echo "<OPTION value='$desi'>$desi</OPTION> ";

$i=$i+1;

} ?></select>

&nbsp

</form></td></tr>

</body>

</html>

am_25 · February 12, 2007

Thanks I tried the Online tools example, but it does not work when I retrieve data from the DB.

When the OPTION VALUES are given it works, but when it is retrieved from the DB, the array does not pass any value.

It is very weird

thepip3r · February 12, 2007

ok then.. try this because this doesn't make sense. I've gone over your code but can't seem to find a problem so here's what i want you to do. Load the page so that your db query runs and builds your select box. Then view source on that page and post the results here. i want to see how the raw HTML output looks.

am_25 · February 12, 2007

Thanks a lot Here is the raw HTML code

<pre>Array

(

[test] =>

[submit] => submit

)

</pre>You selected value. <br /><html>

<body>

<OPTION value='Manger'>Manger</OPTION> <OPTION value='Mgr'>Mgr</OPTION> <OPTION value='QA'>QA</OPTION> <OPTION value='SE'>SE</OPTION> <OPTION value='SSE'>SSE</OPTION> </select>

&nbsp

</form></td></tr>

</body>

</html>

kenrbnsn · February 12, 2007

You have an extraneous "</form></td></tr>" at the end of your source, but that shouldn't make a difference.

I took your code and ran it on my server and it works fine. What version of PHP, type of webserver, and browser are you using?

Ken

am_25 · February 13, 2007

I'm using PHP 5.0, IE 6.0

13th_Star · February 13, 2007

instead of if ($text) { foreach try if ($test == !"") { foreach

am_25 · February 13, 2007

Apache 2.2.4

Jessica · February 13, 2007

instead of if ($text) { foreach try if ($test == !"") { foreach

That doesn't make sense. If test is going to be an array, check the count();

if(count($test)){

}

13th_Star · February 13, 2007

instead of if ($text) { foreach try if ($test == !"") { foreach

That doesn't make sense. If test is going to be an array, check the count();

if(count($test)){

}

well everytime I try to use if($blabla) it does fuck all lol

am_25 · February 13, 2007

I think it is something to do with PHP 5

am_25 · February 13, 2007

This works

<?php
echo '<pre>' . print_r($_POST,true) . '</pre>';

$test=$_POST['test'];
if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
?>
<html>
</body>
<form action="test.php" method="post">

<select name="test[]" multiple="multiple">
<option value="one">one</option>
<option value="two">two</option> 
<option value="three">three</option>
<option value="four">four</option> 
<option value="five">five</option>
</select> 
&nbsp
<input type='submit' name='submit' value='submit'>
</form>
</body>
</html>

This does not work, what can the error be, except that the values are from the DB. It is not passed in the array varible. But for a variable it works.

<?php
include "connect.php";
echo '<pre>' . print_r($_POST,true) . '</pre>';
if (isset($_POST['submit']))
{	
$test=$_POST['test'];
$n=count($test);
if (count($test)){
   echo " you are inside the loop";
}
echo "You selected ".$test." value. <br />";
if ($test){
 foreach ($test as $t){echo 'You selected ',$t,'<br />';}
}
}
?>
<html>
<body>
<form action="multiple.php" method="post">
<?php
$sql2="SELECT distinct(designation) from empdet order by designation asc ";
$result2=mysql_query($sql2);?>
<SELECT name="test[]" multiple ="multiple">
<?php
While ($row=mysql_fetch_assoc($result2))
{
//$desi=$row['designation'];
echo "<OPTION  value=\"{$row['designation']}\">{$row['designation']}</OPTION>\n";
} ?></select>
<input type='submit' name='submit' value='submit'>
</form>
</body>
</html>

am_25 · February 14, 2007

It worked, the problem was very simple.

the

include "connect.php"; - line was the problem.

Since this line was the first line, all the POST variables were getting lost.

I removed this line of code and placed it just before where the SQL was called and viola everything worked.

Thanks for all the help.

Sign In

[SOLVED] please help - Unable to get value in &_POST for a array variable

Recommended Posts

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Join the conversation

Important Information