Jump to content


creating, connecting and intering data to the database

  • Please log in to reply
3 replies to this topic

#1 greeneel

  • New Members
  • Pip
  • Newbie
  • 7 posts

Posted 06 March 2006 - 01:12 PM


I am learning php and came across this script... (Script Attached) while using the book. Beginning PHP, Apache, Mysql Web Development.

and im getting this error: and i have a few questions
Fatal error: Call to undefined function: mysql_connect() in c:\wamp\www\createmovie.php on line 4

Now I don`t see why this isn`t working because in the book it said to download:PHP: 4.3.3, Apache: 2.0.47, Mysql: 4.0.15a and i`m following the book. Now I installed php 4.3.3, apache 2.0.47 but wasn`t able to find mysql 4.0.15a binary for windows so I installed mysql 5 most recent stable version as of today.
I am confused because following this book gets me nowhere when running this script but according to them it should work..Is it because i never got the mysql 4.0.15a? don`t see how a person writes a book to teach you something and seem to assume u know something about it already..

Can anyone tell me how to get around this connect problem ini this script?
Does anyone have any other ideas on books to point me to that works?
And does a mysql 4.0.15a exist for windows?

//Connect to <Mysql; note we`ve used our own parameters- you should
//use your won for hostname, user and password
$connect = mysql_connect("localhost", "root", "mysqlpass") or
die ("Hey loser, check your server connection.");

//Create the mail database
or die(mysql_error());

//make sure our recently created database is the active one
mysql_select_db ("donda");

//create "movie" table
$movie = "CREATE TABLE movie (
movie_id int(11) NOT NULL auto_increment,
movie_name varchar(255) NOT NULL,
movie_type tinyint(2) NOT NULL default 0,
movie_year int(4) NOT NULL default 0,
movie_leadactor int(11) NOT NULL default 0,
movie_director int(11) NOT NULL default 0,
PRIMARY KEY (movie_id)
KEY movie_type (movie_type,movie_year)

$results = mysql_query($movie)
or die (mysql_error());

//Creat "movietype" table
$movietype = "CREATE TABLE movietype (
movietype_id int(11) NOT NULL auto_increment,
movietype_label Varchar(100) NOT NULL,
PRIMARY KEY (movietype_id)

$results = mysql_query($movietype)
or die(mysql_error());

//create "people" table
$people = "CREATE TABLE people (
people_id int(11) NOT NULL auto_increment,
people_fullname varchar(255) NOT NULL,
people_isactor tinyint(1) NOT NULL default 0,
people_isdirector tinyint(1) NOT NULL default 0,
PRIMARY KEY (people_id)

$results = mysql_query($people)
or die(mysql_error());

echo "Movie Database successfully created!";

#2 wickning1

  • Members
  • PipPipPip
  • Advanced Member
  • 405 posts

Posted 06 March 2006 - 02:36 PM

PHP uses an extension called "mysql" to communicate with MySQL. This extension must be specifically activated when you compile PHP.

My guess is that you did not do this. Read the installation instructions on php.net carefully and try compiling again.

#3 fenway

  • Staff Alumni
  • MySQL Si-Fu / PHP Resident Alien
  • 16,199 posts
  • LocationToronto, ON

Posted 06 March 2006 - 07:20 PM

Agreed -- check the extensions in your php.ini file, make sure the extension path is specified correctly, there are apache things to handle as well. All of this is covered in the PHP installation documentation, as wickning1 mentioned.
Seriously... if people don't start reading this before posting, I'm going to consider not answering at all.

#4 wickning1

  • Members
  • PipPipPip
  • Advanced Member
  • 405 posts

Posted 06 March 2006 - 07:56 PM

Also if you are just starting out, you may want to try a precompiled package of binaries like XAMPP.

0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users