Variables whithin a string ( is there too many quotation marks)

[madspof]

Hi I am trying to place a dynamic src url for an image in a echo function, but I think the reason the script is not working is because of the amount of quotation mark in the echo function.

Here is the code i am try to insert it to:

    echo "<IMG SRC='{$row['url']}' ALT='Starflower'> <br><br><br>";

 

[BlueSkyIS]

No. Put this before that line and see yourself:

 

$row['url'] = "test";

 

$row['url'] must be empty if you're not seeing anything there.

[darkfreaks]

Try

 

 echo "<IMG SRC='$row['url']' ALT='Starflower'> <br><br><br>";

[BlueSkyIS]

^^ THAT will not work.

[madspof]

I tested all those options and they did not work but i cannot sem to get it to work correctly.

[madspof]

I tried using the concatenation operator to enter the url in but with no luck

[darkfreaks]

<?php echo "<IMG SRC=\"".$row['url']."\ ALT="Starflower"> <br><br><br>";?>

 

 

 

[Jessica]

<?php echo "<IMG SRC=\"".$row['url']."\ ALT="Starflower"> <br><br><br>";?>

 

Close, but not quite. Try:

<?php echo '<IMG SRC="'.$row['url'].' ALT="Starflower"> <br><br><br>';?>

[darkfreaks]

lol i just tried to escape it thanks.