[SOLVED] Remove style tags

[The Little Guy]

$getvid returns all html from a website.

 

I have tried this:

<?php preg_replace("~\<style(.*)\>(.*)\<\/style\>~"," ",$getvid); ?>

 

It doesn't work, all I want to do is remove the style tags, and everything between them. In there place I want to insert a space.

[The Little Guy]

I think I got it using thsi:

 

"/<((?:style)).*>.*<\/\\1>/si",

 

but I guess we will see

[The Little Guy]

<?php $getvid = preg_replace("/<((?:style)).*>.*<\/style>/si", ' ',$getvid); ?>

 

OK... This doesn't work... any help? for some reason it returns a blank page.

[roopurt18]

I've found that the preg_* functions seem to crash when the string you're applying the regexp gets large.  Try using the regexp on a smaller string first and see if it succeeds.

[The Little Guy]

I found if I remove the "s" at the end, it doesn't quit, but at the same time it doesn't remove the styles

[sasa]

try

$getvid = preg_replace('/<\s*style.+?<\s*\/\s*style.*?>/', ' ', $getvid );

[The Little Guy]

nope... didn't work

[Jessica]

You could use substring and strpos to remove everything between

<style> and </style>[code]

[/code]

[dsaba]

I use this function to grab things inside of markers

you can use preg_replace on it

its the concept I suppose of what you're asking, play around with it, also your problem might be stripping line breaks before you parse through any source code, <span> is different from <span>\n

 

function get_insideMarkers($left, $right, $raw) {
$leftMarker = preg_quote($left, '/');
$rightMarker = preg_quote($right, '/');
$findBulk = preg_match_all('/'.$leftMarker.'(.*?)'.$rightMarker.'/', $raw, $array);
$resultArray = $array[1];
return $resultArray;
}

function stripnl($text) {
$text = str_replace("\r\n", "", $text);
$text = str_replace("\r", "", $text);
$text = str_replace("\n", "", $text);
return trim($text);
}

$raw = stripnl(file_get_contents('url'));
$array = get_insideMarkers('<span>', '</span>', $raw);
print_r($array); //returns all span tags

[sasa]

try

$getvid = preg_replace('/<\s*style.+?<\s*\/\s*style.*?>/si', ' ', $getvid );