[SOLVED] How many hours have I lived script...

[phpSensei]

listen, I am really confused about my script and I dont think this is even a little accurate...

 

Script shows how many hours, have I lived in my life...

 

how does this work?

 

<?php

$current_year = date("Y");
//This Year

$year = $_POST['year'];
//Born Year

$years_lived = $current_year - $year;
// How many years the user has lived // 
$months_total = 12 * $years_lived;
// How many months lived // 
$days_lived = 365 * $months_total;
// How many days lived //
$hours_lived = 24 * $days_lived;
// How many Hours Lived //



?>

How should I make so it takes my full birthday - today...

 

Example:

 

Born : 12, june, 1988

 

and that date minus

 

4, september, 2007...

 

[sstangle73]

heres a script that gives you age in years

 

function birthday($birthday){   
list($month,$day,$year) = explode("-", $birthday);  

$today = getdate();   
$age = $today['year']-$year;
   
if(($month > $today['mon']) || ($month==$today['mon'] && $day > $today['mday'])){   


$age--;
}

return $age;  
}

 

im not sure what your question is?  your script is only accurate on your birthday and the year is wrong if you havent had your bday this year.

 

[Barand]

<?php
$dob = '12-jun-88';

$hours = (time() - strtotime($dob) ) / 3600;
?>

[phpSensei]

<?php
$dob = '12-jun-88';

$hours = (time() - strtotime($dob) ) / 3600;
?>

 

I tried thhis...

 

<?php

if(isset($_POST['submit'])){

$name = trim($_POST['name']);
$yr = $_POST['year'];
$mt = $_POST['month'];
$dy = $_POST['days'];

if(($name == "")||($yr=="0")||($mt=="0")||($dy=="0")){

die("Please enter your name, and full date of birth");

}
else
{
$year_today = date ('Y');
$month_today = date ('m');
$day_today = date ('d');

$birth_day = $_POST['days'];
$birth_month = $_POST['month'];
$birth_year = $_POST['year'];


$how_many_years = $year_today - $birth_year;
$total_month = $how_many_years * 12;
$total_days = $total_month * 30;

$how_many_days_inbirth =  $total_days ; 

$total_days_1 = $how_many_days_inbirth; //5475

/////////////////////////////////////////////////////////
$count_current_month = 30 * $month_today + $day_today;  // 30 * 09 + 04

$total_days_2 = $count_current_month;
/////////////////////////////////////////////////////////

$days_lived = $total_days_1 + $total_days_2;


echo '<table width="55%" border="0" align="center" cellpadding="0" cellspacing="2">
  <tr>
    <td align="left" valign="top"><h2 align="center" class="style1">'.$name.' , we have estimated that you have lived for: <span class="style3">'.$days_lived.' days</span></h2>    </td>
  </tr>
  <tr>

[Jessica]

Unless you allow the user to enter the time of day they were born, it won't be accurate.

You'd also have to account for where they were born, where they are, and where your server is. Time zones.

I'd use timestamp() instead of messing with the year and then multiplying it, but without the other info the closest you can be is within 24 hours I guess.

[phpSensei]

they enter a form if thats what you ment...

 

yeah, I have to upgrade the script...

 

like i said, just a challenge.

[AndyB]

I'd use timestamp() ...

... but only for young folk.

[Jessica]

Good point