[SOLVED] Is this possible? Variables through img src

[papaface]

Hello,

I am trying to pass a variable through an image. Like this:

<img src="http://www.*****.com/test.php?url=1234" />

 

In test.php I have this code:

<?php
session_start();

$_SESSION['url'] = $_GET['url'];

?>

 

But this doesnt seem to set $_SESSION['url'] to 1234

 

Does anyone know a way I can get this to work?

 

regards

[EvanAgee]

Perhaps if you can describe the desired end result I can better assist.

[TheFilmGod]

how can you pass the variable via image src?? - you can't!!!

 

You can do it through a link or an address, not an image src.

 

Try

<a href="http://www.website.com/test.php?url=1234"><img src"..." /></a>

 

LIke that?

[papaface]

Scripts can be called from an image src so I don't see why variables cant be used in it aswell....

How do you think captchas are generated.

I am well aware you can pass a variable through a link.

Perhaps if you can describe the desired end result I can better assist.

 

I want to call the image file, create a session var with the parameter in the image src code.

[papaface]

The image src wouldnt be an image it would be a script remember. So nothing would load.

[EvanAgee]

You're right, it does seem that you would be able to pass variables, even if the script is being called as an image source. I specifically recall seeing a script that was used to generate an image and it contained variable references and declarations. Maybe there's a limit on the type of session-related activity you can perform when accessing a script this way? Best of luck!

[EvanAgee]

The image src wouldnt be an image it would be a script remember. So nothing would load.

 

You can use the header() to display an image.

[papaface]

I think this may have something to do with the fact the variable isnt in an address bar, so therefore $_GET can't be used  ???

You can use the header() to display an image.

I don't want to display an image.

[TheFilmGod]

I think this may have something to do with the fact the variable isnt in an address bar, so therefore $_GET can't be used  ???

You can use the header() to display an image.

I don't want to display an image.

 

Lol. That is what I was talking about! DuH! Hit the books mister!

[EvanAgee]

Could be, why exactly are you using an <img> tag if you're not displaying an image?

[TheFilmGod]

Could be, why exactly are you using an <img> tag if you're not displaying an image?

 

No. That is right. Come on 1st grade php. You can't extract $_GET parameters unless they are in the address bar.

 

Try using $_FILE instead or $_SESSION

 

[papaface]

No. That is right. Come on 1st grade php. You can't extract $_GET parameters unless they are in the address bar.

 

Try using $_FILE instead or $_SESSION

What the hell is wrong with you. Cant you just reply in a kind manner, than in an offensive and immature tone.

Try using $_FILE instead or $_SESSION

and only a 1st grader in PHP would offer those two as a solution.

Could be, why exactly are you using an <img> tag if you're not displaying an image?

Its complicated lol. An image is produced it is a captcha script. I just wanted to simplify things as it isn't really an important point to make.

[EvanAgee]

I think this may have something to do with the fact the variable isnt in an address bar, so therefore $_GET can't be used  ???

You can use the header() to display an image.

I don't want to display an image.

 

Lol. That is what I was talking about! DuH! Hit the books mister!

 

Just to clarify, FilmGod, you can "generate" an image using a PHP script. I could link to <img src="foo.php"> and have it display as an image.

[TheFilmGod]

I think this may have something to do with the fact the variable isnt in an address bar, so therefore $_GET can't be used  ???

You can use the header() to display an image.

I don't want to display an image.

 

Lol. That is what I was talking about! DuH! Hit the books mister!

 

Just to clarify, FilmGod, you can "generate" an image using a PHP script. I could link to <img src="foo.php"> and have it display as an image.

 

huh? src="foo.php". Don't pull a fast one on me. That aint' no image. You can use <a href=""></a> instead. Why image anyway. 1st grade html come on!

[TheFilmGod]

Actually. I take that back. But it would have been better to generate the image before and then have it in the cache or watever before hand.

[papaface]

For goodness sake!

and image can be called from a php script. You obviously do not know what you are talking about, and are therefore posting irrelevant info in my thread.

Go elsewhere!

 

Now back on topic. Theoretically you should be able to post the vars in the src. hmmm..

[EvanAgee]

Actually. I take that back. But it would have been better to generate the image before and then have it in the cache or watever before hand.

 

You expertise is no longer required FilmGod ha ha.

[EvanAgee]

For goodness sake!

and image can be called from a php script. You obviously do not know what you are talking about, and are therefore posting irrelevant info in my thread.

Go elsewhere!

 

Now back on topic. Theoretically you should be able to post the vars in the src. hmmm..

 

Yes, you should. I know I've seen it work with $_GET's before, just not sure about sessions. I can see why the session data wouldn't be retained if you're using the img src to set it, but not exactly sure what the facts are on the matter. Let me do some quick digging.

[trq]

Why image anyway. 1st grade html come on!

 

Seriously, you have no idea what you are on about. You can use php to generate images. I have often used img src tags like...

 

<image src="image.php?id=foo">

 

You then have your image.php file generate the image using the gd functions and apprpriate headers. Funnily enough, sourcing an image via the src tag makes a GET request.

 

papaface.... can we please see your actual code?

[papaface]

hmm. I have just tried it and I think it is working. Which is strange as it wasnt before. Give me to minutes to clarify.

[papaface]

Ahhh it is lol.

Thanks for your help guys!

[EvanAgee]

Good, because it was confusing that it wouldn't work