Leaderboard
Popular Content
Showing content with the highest reputation on 06/15/2021 in all areas
-
Don't use "SELECT * ". Specify the columns you want. This makes it easier for others, like me, to understand what is in the table and what the query is doing. Indent your code to show the nested structure of loops etc. If you had done those I might have given this problem more than a cursory glance. So you'll have to settle for a generic example of using a recursive function to give an indented list of parent/child elements. Also, Don't run queries inside loops. Use JOINs to get all the data in a single query THE DATA TABLE: category +----+---------+--------+ | id | name | parent | +----+---------+--------+ | 1 | happy | 0 | | 2 | comet | 0 | | 3 | grumpy | 0 | | 4 | prancer | 1 | | 5 | bashful | 1 | | 6 | dancer | 2 | | 7 | doc | 2 | | 8 | blitzen | 2 | | 9 | dasher | 3 | | 10 | donner | 1 | | 11 | vixen | 1 | | 12 | cupid | 8 | +----+---------+--------+ THE OUTPUT THE CODE <?php $sql = "SELECT id, name, parent FROM category"; $res = $db->query($sql); // // store arrays of items for each parent in an array // while (list($id, $name, $parent) = $res->fetch(PDO::FETCH_NUM)) { $data[$parent][] = array('id'=>$id, 'name'=>$name); } /** * recursive function to print a category then its child categories * * @param array $arr category data * @param int $parent parent category * @param int $level hierarchy level */ function displayHierarchy(&$arr, $parent, $level=0) { if (isset($arr[$parent])) { echo "<ul>\n"; foreach($arr[$parent] as $rec) { echo "<li class='li$level'>{$rec['name']}\n"; if (isset($arr[$rec['id']])) displayHierarchy($arr, $rec['id'], $level+1); echo "</li>\n"; } echo "</ul>\n"; } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Example</title> <link rel="stylesheet" href="https://www.w3schools.com/w3css/4/w3.css"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <script type="text/javascript"> </script> <style type="text/css"> body { font-family: verdana,sans-serif; font-size: 11pt; padding: 50px; } li { font-weight: 600;} .li0 { color: red; } .li1 { color: green; } .li2 { color: blue; } </style> </head> <body> <?php displayHierarchy($data, 0); ?> </body> </html>
2 points -
You entered "j" and it's listing records with user containing "j". So I don't see what's wrong with that. Are you talking about getting all those duplicates? It's because you're joining the login and dados_user tables together without telling MySQL how to join them together. You need a query that looks like SELECT login.user, dados_user.nome_proprio FROM login JOIN dados_user ON login.??? = dados_user.??? WHERE login.user LIKE '%$procura%' AND login.eliminado = 01 point
-
https://www.letmegooglethat.com/?q=install+mysql+on+linux0 points
This leaderboard is set to New York/GMT-04:00