Search the Community
Showing results for tags 'button'.
-
Using Joomla 2.5 and Virtuemart 3. I've had a client tell us that they're getting e-mails (admin order confirmation email) that are different orders from the same person at the same time. After some test orders I've seen that what happens is when PayPal is used, and the customer is being redirected or has been, they then press the back button in the browser, amend the order and send it again. This sends 2 e-mails to the shop and causes confusion. Is there a way to stop this? (Other than a big bold message warning not to do it)
-
- joomla
- virtuemart
-
(and 3 more)
Tagged with:
-
Say I have button 1 and I want to replace it with button2 on click. How would I do that? <button id="button1">butto 1</button> <button id="button2">butto 2</button>
- 2 replies
-
- ajax
- javascript
-
(and 3 more)
Tagged with:
-
This twitter style button I found. http://jsfiddle.net/jakie8/ZECEN/ I have managed to modify it to my liking. And yes I know the ".live" is depreciated and instead use "on". Anyways, the only thing I noticed is that if I click "Follow" button and it turns green; once I refresh the page, it goes back to default "follow" mode. I was wondering how can I keep it green even if I refresh the page?
- 3 replies
-
- ajax
- javascript
-
(and 3 more)
Tagged with:
-
The like/dislike button script found here: http://wcetdesigns.com/tutorials/demos/like-dislike-button.html works perfectly for what I am trying to do on my webpage. The issue I am having is I can connect to one table perfect but the script breaks if I try to add another set of like/dislike buttons that connects to another table. How can I add 2 additional like/dislike button sets that can connect to 2 addtional tables in my database. For example Topic name (like/dislike button set that connects to table 1) Messages (like/dislike button set that connect to table 2) Message Replies (like/dislike button set that connects to table 3) any help would be appreciated. Thanks
-
$liked = explode(":", $_POST[submit]); if($liked[0] == "like"){ //Select from database where id is $liked[1] } <input type="image" src="images/arrowup.gif" name="submit" value="like:<? echo $right->id; ?>"/> Ok, so i have made a forum and i have a like function running on the comments of a post. I needed to find a way when the image was clicked it updated the database. So i experimented and came up with the solution above having it explode the value of the button to read if it was press and get the id. It works perfectly but i just want to be convinced it is safe.