[SOLVED] Function to get image type?

[Andy-H]

Does anyone know of one to get the image type from an fopen or from an image url?

 

Thanks for any help.

[gevans]

http://uk2.php.net/manual/en/function.exif-imagetype.php

 

That takes you to the exif_imagetype() page of php.net

 

Very easy to use, but you do need to have EXIF installed on the server.

[Andy-H]

thanks

[Andy-H]

exif isnt installed

[gevans]

You could work backwards.

 

Once you have the URL, use substr to return the last 4 characters

 

$image = "example.jpg";
$ext = substr($image, -4);
if($ext == ".jpg") echo "This is a jpg";
else echo "This is a different image type";

 

This will only work if you know what extensions you are looking for

[Andy-H]

I need the header image type because they have the .jpg extension for all images yes some are png, I only want to display the jpg images.

[gevans]

OK, try this....

 

<?php
list($width, $height, $type, $attr) = getimagesize("img/flag.jpg");
echo $type;
?>

[Andy-H]

k ty m8 will do when I get back to college.

[ILMV]

Hang on... what if the image is .jpeg?

 

http://en.wikipedia.org/wiki/JPEG

[Andy-H]

Got it, ty for help

 

$fp = fopen($file, 'r');

if ($fp){

      $type = getimagesize($file);
      $type = $type['mime'];

   if ($type == "image/jpeg"){

 

[gevans]

Hang on... what if the image is .jpeg?

 

http://en.wikipedia.org/wiki/JPEG

 

Then he would check it against '.jpg' and 'jpeg' (i didn't choose four characters fr the dot)

[Andy-H]

Besides, I could just use:

 

$file = "http://www.example.com/pic.jpeg";

$file = explode(".", $file);
$index = count($file) - 1;

$extention = $file[$index];

[gevans]

Besides, I could just use:

 

$file = "http://www.example.com/pic.jpeg";

$file = explode(".", $file);
$index = count($file) - 1;

$extention = $file[$index];

 

Yea, there's a few options, but you're $type['mime'] seems like the ebst option for you