Jump to content

Recommended Posts

I am trying to build an account system, here are the files:

new_user.php

<form action="process/new_user_process.php" method="post">
<tr>
<td>Nombre de usuario:</td><td><input type="text" name="username" maxlength="30"></td>
</tr>
<tr>
<td>Contraseña: </td><td><input type="password" name="password" maxlength="30"></td>
</tr>
<tr>
<td>Re-escribir contraseña: </td><td><input type="password" name="repassword" maxlength="30"></td>
</tr>
<tr>
<td>Nombre: </td><td><input type="text" name="nombre" maxlength="30"></td>
</tr>
<tr>
<td>Apellido: </td><td><input type="text" name="apellido" maxlength="30"></td>
</tr>
<tr>
<td>Correo electronico: </td><td><input type="text" name="email" maxlength="30"></td>
</tr>
<tr><td><input type="submit" name="submit" value="Aceptar"></td></tr>

</form>

 

And here is the script containing the class:

new_user_process.php

<?php require_once("includes/connection.php"); 

class User{
function addUser($username, $hash_password, $nombre, $apelllido, $email, $userlevel){
	$this->username = mysql_real_escape_string($_POST['username']);
	$this->hash_password = sha1($_POST['hash_password']);
	$this->nombre = $_POST['nombre'];
	$this->apellido = $_POST['apellido'];
	$this->email = $_POST['email'];
	$this->userlevel = $_POST['userlevel'];
	$this->query = "INSERT INTO users  
			VALUES ({$this->username}, {$this->hashed_password}, {$this->nombre}, {$this->apellido},
			{$this->email}, {$this->userlevel})";
	return mysql_query($this->query, $this->connection);
}
}
$user = new User();
?>

the second file is contained in the process subfolder, that's why the form action is process/new_user_process.php

The problem is the data is not being entered into the table.

 

Thanks very much

Link to comment
https://forums.phpfreaks.com/topic/134532-add-account-class-question/
Share on other sites

Im using a class to insert fields into a table:

<?php class User{
public function addUser($username, $hash_password, $nombre, $apelllido, $email, $userlevel){
	$this->username = mysql_real_escape_string($_POST['username']);
	$this->hash_password = sha1($_POST['hash_password']);
	$this->nombre = $_POST['nombre'];
	$this->apellido = $_POST['apellido'];
	$this->email = $_POST['email'];
	$this->userlevel = $_POST['userlevel'];
	$this->query = "INSERT INTO users  
			VALUES ({$this->username}, {$this->hashed_password}, {$this->nombre}, {$this->apellido}, {$this->email}, {$this->userlevel});";
	return mysql_query($this->query, $this->connection);
}
}
$user = new User();
$user->addUser($this->username, $this->hash_password, $this->nombre, $this->apellido, $this->email, $this->userlevel);
?>

 

Im getting "Using $this when not in object context"

 

When I try to pass the method arguments as:

<?php$user = new User();
$user->addUser($username, $hash_password, $nombre, $apellido, $email, $userlevel);?>

 

I get "mysql_query(): supplied argument is not a valid MySQL-Link resource in C:\wamp\www\vanvien\new_user_process.php on line 14"

 

:'( :'( I am very frustrated... please help!

Thanks

 

This line:

 

$user->addUser($this->username, $this->hash_password, $this->nombre, $this->apellido, $this->email, $this->userlevel);

 

Is the source of your problem.  Like the error says, you can't use '$this' outside of an object.  What you should be doing is the following:

 

class User
{
   public function addUser($userName, $hashPassword, $nombre, $apellido, $email, $userLevel)
   {
      $this->username = mysql_real_escape_string($userName);
      $this->hash_password = sha1($hashPassword);
      $this->nombre = $nombre;
      $this->apellido = $apellido;
      $this->email = $email;
      $this->userlevel = $userLevel;
      $this->query = "INSERT INTO users VALUES ({$this->username}, {$this->hash_password}, {$this->nombre}, {$this->apellido}, {$this->email}, {$this->userlevel});";

      return mysql_query($this->query, $this->connection);
   }
}

$user = new User();
$user->addUser($_POST['username'], $_POST['hash_password'], $_POST['nombre'], $_POST['apellido'], $_POST['email'], $_POST['userlevel']);

1. $this->connection is included at the top in an external file, just forgot to paste it.

 

2. using $POST[''] I think the hole concept of oop is lost. Besides for example, the record added in the hash_password field would not have the encryption sha1().

 

And using your solution I still get "mysql_query(): supplied argument is not a valid MySQL-Link resource".

 

I really appreciate you guys trying to help me

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.