[SOLVED] date() question

[ballhogjoni]

How can I find out how many have gone by this year? for example, I need to know how many days have gone by since 01/01/2008 to 07/22/2008. Anyone have any good ideas? thx.

[premiso]

You could do a loop like so:

 

<?php
$bContinue = true;
$sDate = strtodate("01/01/2008");
$eDate = strtodate("07/22/2008");
$i=0;
while ($eDate > $sDate) {
    $sDate = $sDate + (60*60*24); // one date 
    $i++; 
}

echo $i . " days have passed.";

 

There may be a better way, but that should work.

[Maq]

Not sure if you can use arithmetic like this but:

 

$sub = strtotime(07/22/2008) - strtotime(01/01/2008); //get  timestamp (seconds)
$sub = ($sub/3600) / 24; // get days seconds / 60*60*24 = 1 day
echo int_val($sub); //round to nearest integer

[flyhoney]

<?php
$day1 = date('z', strtotime('01/01/2008'));
$day2 = date('z', strtotime('07/22/2008'));
echo "Days between: " . ($day1 - $day2);
?>

[flyhoney]

Or this maybe:

 

<?php
$diff = strtotime('01/01/2008') - strtotime('07/22/2008');
$days = $diff / 3600;
echo "Days between: " . $diff;
?>

[Maq]

Wouldn't:

 

$days = $diff / 3600;

 

give you hours?  60(secs)*60(minutes) = hours

[flyhoney]

Wouldn't:

 

$days = $diff / 3600;

 

give you hours?  60(secs)*60(minutes) = hours

 

Definitely, screwed up my mathz.

 

$days = $diff / (60 * 60 * 24);