Call a function with parameters stored within a variable as a String.

[tmh766]

Is this possible?

 

For example

 

$variable="functionOne('param1','param2')";

 

Another example

 

$varaible2="functionOne(functionTwo(1))";

 

Is it possible to execute $variable which would then call functionOne and pass it its parameters? And is it possible to execute $variable2 which would call functionOne which would call functionTwo?

[Maq]

What gives you doubt?  Have you tried it?

[tmh766]

I don't understand how to execute $variable, $variable() would not work as its not just a function name, but one with parameters.

[kaf723]

Dude, it's so easy, it's like one line of code.

 

It works bro!

[kaf723]

Okay dude, like , for example, an MD5 Hash

 

generatePassword(){

your code;

 

}

 

 

$variable1=md5(generatePassword());

[Maq]

Here's another basic example:

 

function f1($var1){
   $what = $var1;
   return $what;
}

function f2($var2){
   $what2 = $var2 + 2;
   return $what2;
}

$variable = f1(f2(1));
echo $variable;

?>

 

As long as f2 returns something it will pass it to f1 which returns $what and variable is assigned to it.

 

[tmh766]

Hey

 

I can't do it like that though because the function is a String. What I was looking for was eval(), I can call

 

eval($variable)

so as long as $variable had return ahead of the function.

[premiso]

I am having a hard time understanding what the user is getting at.

 

But why not use the call_user_func method? That is what it was intended for, from what I gathered on the OP.