[SOLVED] How do I compare a variable to a function array?

[pneudralics]

Want to compare name from form to badword list, but can't seem to get it to compare.

function badword() {
  array("badword1","badword2","badword3")
}
$badword = badword();
//$name comes from form
$name = $_POST['name'];
if ("$name" != "$badword") {
//if not badword do this
}
else {
//bad word
}

[kenrbnsn]

Use in_array

 

<?php
$badwords = array("badword1","badword2","badword3");
if (!in_array($_POST['name'],$badwords)) {
//
//  not a bad word
//
} else {
//
// bad word
//
}
?>

 

Ken

[pneudralics]

I seem to get: Wrong datatype for second argument

When I try your example.

 

I notice when I try to echo the below I don't get any output except Array.

$badwords = array("badword1","badword2","badword3");
echo "$badwords";

[pneudralics]

Also tried the below and got Invalid argument supplied for foreach()

$badwords = badword();
foreach($badwords as $value)
{
echo "$value";
}

[DarkWater]

That's because your badwords() function doesn't actually do anything in its current state.  Plus you're missing a ;.

[pneudralics]

That's because your badwords() function doesn't actually do anything in its current state.  Plus you're missing a ;.

 

Shouldn't the foreach display the array? Where does the ; go?

[Philip]

function badword() {
  array("badword1","badword2","badword3")
}

Should be the following for it to work:

function badword() {
  return array("badword1","badword2","badword3");
}

 

As a whole:

<?php
function badword() {
  return array("badword1","badword2","badword3");
}
$badwords = badword();
if (!in_array($_POST['name'],$badwords)) {
//
//  not a bad word
//
} else {
//
// bad word
//
}

 

[pneudralics]

Thanks the return() fixed the issue