I know this is a stupid question

[elentz]

This is so simple but I can't get it to work.

 

I have two variables:

 

$total

$mitax

 

I want to subtract $mitax from $total to get $subtotal

 

Here is what I have:

 

$subtotal= $total - $mitax;

 

I already am outputting $mitax and the $total and the amounts are right.  For example $total= 1244.70 and $mitax = 11.70  So the answer should be 1233.00  But I get -10.7  What am I doing wrong?

 

Thanks for looking

[Alex]

Works for me:

 

<?php
$total= 1244.70;
$mitax = 11.70;
$sub = $total - $mitax;

echo $sub;
?>

Output: 1233

[Maq]

Works fine for me.  Post more of the surrounding code.  Where do $total and $mitax come from?

[roopurt18]

We need to see a little bit more code and a little bit more of your program's output to help, because it sounds like it should be working.  But it's not, so you've made a mistake elsewhere.

[Mark Baker]

$total = 1244.70;
$mitax = 11.70;

$subtotal = $total - $mitax;
echo $total.' - '.$mitax.' = '.$subtotal.'<br />';

$total = '1,244.70';
$mitax = '11.70';

$subtotal = $total - $mitax;
echo $total.' - '.$mitax.' = '.$subtotal.'<br />';

gives

1244.7 - 11.7 = 1233
1,244.70 - 11.70 = -10.7

Now go ensure that your $total and $mitax values are actual numbers and not formatted strings

[Ken2k7]

The comma obviously is the problem. Casting the string '1,244.70' as an int would result in the number 1, or whatever the number is up to a non-numeric character, which in this case is the comma.

[roopurt18]

$total = '1,244.70';

 

PHP will convert this to a number before subtracting.  '1,244' converted to a number is 1.

 

http://www.php.net/language.types.type-juggling

[elentz]

Well, Mark had the right idea, I had BOTh of those numbers formatted.  Once I removed that it woked out.  But at some point I need to format the numbers.

 

Thanks guys!

[roopurt18]

Well, Mark had the right idea, I had BOTh of those numbers formatted.  Once I removed that it woked out.  But at some point I need to format the numbers.

 

Format it after all calculations are made or just before display.

[elentz]

That is exactly what I did and it works perfectly,

 

Thanks!